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Differentiate y = (2x + 1)°(x³ – x + 1)*. Solution: In this example we must use the Product Rule before using the Chain Rule: dy (2.x + 1) d (x³ – x + 1)* + (x³ – x + 1) · dx d (2x + 1) dx || dx d = (2x + 1) • 4(x³ – x + 1)³ (x³ – x + 1) dx

Differentiate y = (2x + 1)°(x³ – x + 1)*. Solution: In this example we must use the Product Rule before using the Chain Rule: dy (2.x + 1) d (x³ – x + 1)* + (x³ – x + 1) · dx d (2x + 1) dx || dx d = (2x + 1) • 4(x³ – x + 1)³ (x³ – x + 1) dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I don't understand how each step was obtained to get each value, could you please break down this example as to how each value was obtained because it's very confusing. I have attached the examples in screenshots.

Example 6 Differentiate y = (2x + 1)°(x³ – x + 1)*. - Solution: In this example we must use the Product Rule before using the Chain Rule: d dy (2x + 1)' (x³ – x + 1)* + (x³ – x + 1)+ d (2x + 1)° dx | - dx dx d (x³ – x + 1) dx (2x + 1) · 4(x³ – x + 1)³ .3 - - - + (x³ – x + 1)ª · 5(2x + 1)ª d (2x + 1) dx -
Transcribed Image Text:Example 6 Differentiate y = (2x + 1)°(x³ – x + 1)*. - Solution: In this example we must use the Product Rule before using the Chain Rule: d dy (2x + 1)' (x³ – x + 1)* + (x³ – x + 1)+ d (2x + 1)° dx | - dx dx d (x³ – x + 1) dx (2x + 1) · 4(x³ – x + 1)³ .3 - - - + (x³ – x + 1)ª · 5(2x + 1)ª d (2x + 1) dx -
Example 6 – Solution cont'd = 4(2x + 1)°(x³ – x + 1)°(3x² – 1) + 5(x³ – x + 1)*(2x + 1)* · 2 - Noticing that each term has the common factor 2(2x + 1)*(x³ – x + 1)³, we could factor it out and write the - answer as dy 2(2.x + 1)*(x³ – x + 1)°(17x³ + 6x² – 9x + 3) dx
Transcribed Image Text:Example 6 – Solution cont'd = 4(2x + 1)°(x³ – x + 1)°(3x² – 1) + 5(x³ – x + 1)*(2x + 1)* · 2 - Noticing that each term has the common factor 2(2x + 1)*(x³ – x + 1)³, we could factor it out and write the - answer as dy 2(2.x + 1)*(x³ – x + 1)°(17x³ + 6x² – 9x + 3) dx
Expert Solution
Step 1

Given:-

y =(2x+1)5(x3-x+1)4 

To find:-

Derivative of y

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