Differentiate the function √e-3²+x+1 µ3. f(x)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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6
**Question 6**

Differentiate the function

\[ 
f(x) = \frac{\sqrt{e^{-x^2} + x + 1}}{x^3 - 1} 
\]

Options:

- \[ \frac{\left( -2x^4 - 3x^2 + 2x \right) e^{-x^2} - 2x^3 - 3x^2 - 1}{(x^3 - 1)^2} \]

- \[ \frac{\left( -2x^4 - 3x^2 + 2x \right) e^{-x^2}}{(x^3 - 1)^2} \]

- \[ \frac{-2x^3 + 3x^2 + 1}{(x^3 - 1)^2} \]

- \[ \frac{2xe^{-x^2} - 2x^3 - 3x^2 - 1}{(x^3 - 1) \sqrt{e^{-x^2} + x + 1}} \]
Transcribed Image Text:**Question 6** Differentiate the function \[ f(x) = \frac{\sqrt{e^{-x^2} + x + 1}}{x^3 - 1} \] Options: - \[ \frac{\left( -2x^4 - 3x^2 + 2x \right) e^{-x^2} - 2x^3 - 3x^2 - 1}{(x^3 - 1)^2} \] - \[ \frac{\left( -2x^4 - 3x^2 + 2x \right) e^{-x^2}}{(x^3 - 1)^2} \] - \[ \frac{-2x^3 + 3x^2 + 1}{(x^3 - 1)^2} \] - \[ \frac{2xe^{-x^2} - 2x^3 - 3x^2 - 1}{(x^3 - 1) \sqrt{e^{-x^2} + x + 1}} \]
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