Differentiate the expression for the length of the rope twice to obtain a constraint equation for the accelerations.

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A: Navier-stokes equation (momentum and continuity equations)

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A: Given: →h1=3387.31 KJ/Kg→h2'=3074.5 KJ/Kg→h3=3457.04 KJ/Kg→h4'=3109.82 KJ/Kg→h5'=2384.82…

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Q: friction t

A: FIg:FBD Fr=μN∑Fy=0N=mgcosθ∑Fx=0μN=mgsinθμmgcosθ=mgsinθμ=tanθ