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Differentiate f (x) = 7 (2-60+3). A. f' (2) = a2-6x- 3 B. f' (x) = In(7)(2x–6)7™(=²-6z+3) x2-6x+3 C.f' (x) = In(7) (2x – 6) 7ln(z²–6a+3) In(7) (2² –6x+3)7"(=² Bet3) (2a-6) D. f' (x) =

Differentiate f (x) = 7 (2-60+3). A. f' (2) = a2-6x- 3 B. f' (x) = In(7)(2x–6)7™(=²-6z+3) x2-6x+3 C.f' (x) = In(7) (2x – 6) 7ln(z²–6a+3) In(7) (2² –6x+3)7"(=² Bet3) (2a-6) D. f' (x) =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Differentiate f (x) = 7 (2²-6+3). (2-6)7(2-6z+3) a2-6x- 3 A. f' (x) = B. f' (x) = In(7)(2z-6)7(-²_&z+3) x2-6x+3 C. f' (x) = In(7) (2a – 6) 7ln(a² –6x+3) - D. f' (x) = In(7) (2² – G2+3)=(² de+>) (2a-6)
Transcribed Image Text:Differentiate f (x) = 7 (2²-6+3). (2-6)7(2-6z+3) a2-6x- 3 A. f' (x) = B. f' (x) = In(7)(2z-6)7(-²_&z+3) x2-6x+3 C. f' (x) = In(7) (2a – 6) 7ln(a² –6x+3) - D. f' (x) = In(7) (2² – G2+3)=(² de+>) (2a-6)
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