dielectric-filled parallel-plate capacitor has plate area AAA = 30.0 cm2cm2 , plate separation ddd = 10.0 mmmm and dielectric constant kkK = 3.00. The capacitor is connected to a battery that creates a constant voltage VVV = 5.00 VV . Throughout the problem, use ϵ0ϵ0epsilon_0 = 8.85×10−12 C2/N⋅m2C2/N⋅m2 . The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2U2U_2 of the capacitor at the moment when the capacitor is half-filled with the dielectric. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
A dielectric-filled parallel-plate capacitor has plate area AAA = 30.0 cm2cm2 , plate separation ddd = 10.0 mmmm and dielectric constant kkK = 3.00. The capacitor is connected to a battery that creates a constant voltage VVV = 5.00 VV . Throughout the problem, use ϵ0ϵ0epsilon_0 = 8.85×10−12 C2/N⋅m2C2/N⋅m2 . The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2U2U_2 of the capacitor at the moment when the capacitor is half-filled with the dielectric. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3U3U_3.In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work WWW is done by the external agent acting on the dielectric?
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