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Diameter of the disc = 110.3 mm %3D Radius of the disc, r = ..mm Area of disc = r² Thickness of the disc, h = 10.5 mm Mass of the disc, m = 803 g Thickness of the experimental disc (say cardboard sheet), d = 1.70 mm Steady temperature of the steam chamber, T1 = 73 °C Steady temperature of the brass disc, T2 = 55 °C %3D Time (min) 0 2 4 6 8 10 12 | 14 16 18 20 22 24 26 28 30 Temperature 59 58 57 56 56 56 55 54 53 52 51 50 49 48 47 46 (°C) de From the graph, dt slope = Rate of cooling The Thermal Conductivity constant may be calculated as de m xc X xd k= - A(T-T2) ..equation 4 Where c= Specific heat capacity of brass=------ (Standard value)

Diameter of the disc = 110.3 mm %3D Radius of the disc, r = ..mm Area of disc = r² Thickness of the disc, h = 10.5 mm Mass of the disc, m = 803 g Thickness of the experimental disc (say cardboard sheet), d = 1.70 mm Steady temperature of the steam chamber, T1 = 73 °C Steady temperature of the brass disc, T2 = 55 °C %3D Time (min) 0 2 4 6 8 10 12 | 14 16 18 20 22 24 26 28 30 Temperature 59 58 57 56 56 56 55 54 53 52 51 50 49 48 47 46 (°C) de From the graph, dt slope = Rate of cooling The Thermal Conductivity constant may be calculated as de m xc X xd k= - A(T-T2) ..equation 4 Where c= Specific heat capacity of brass=------ (Standard value)

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Experiment :LEE’S DISC

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Diameter of the disc Radius of the disc, r = 110.3 mm %3D .mm Area of disc = n r² %3D ....... Thickness of the disc, h = 10.5 mm Mass of the disc, m = 803 g Thickness of the experimental disc (say cardboard sheet), d = 1.70 mm Steady temperature of the steam chamber, T1 = 73 °C Steady temperature of the brass disc, T2 = 55 °C Time (min) 10 12 14 16 18 20 22 24 26 28 30 2 4 8 Temperature 59 58 57 56 56 56 55 54 53 52 51 50 49 48 47 46 (°C) de From the graph, slope = Rate of cooling dt The Thermal Conductivity constant may be calculated as de m xc x- xd k = .equation 4 A(T1-T2) Where c= Specific heat capacity of brass=- (Standard value)
Transcribed Image Text:Diameter of the disc Radius of the disc, r = 110.3 mm %3D .mm Area of disc = n r² %3D ....... Thickness of the disc, h = 10.5 mm Mass of the disc, m = 803 g Thickness of the experimental disc (say cardboard sheet), d = 1.70 mm Steady temperature of the steam chamber, T1 = 73 °C Steady temperature of the brass disc, T2 = 55 °C Time (min) 10 12 14 16 18 20 22 24 26 28 30 2 4 8 Temperature 59 58 57 56 56 56 55 54 53 52 51 50 49 48 47 46 (°C) de From the graph, slope = Rate of cooling dt The Thermal Conductivity constant may be calculated as de m xc x- xd k = .equation 4 A(T1-T2) Where c= Specific heat capacity of brass=- (Standard value)
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