diagram below, ABCD is a trapezium, AD||BC and AB⊥BC. The coordinates of D(0;1). The equation of the line BC is 2y-x+4=0. The gradient of AB is -2. The equation of straight line AB is y+2x+2=0. 1.2. E(12;y) is a point on BC produced 1.2.1. Determine the value of y 1.2.2. Given that C is the midpoint of BE, calculate the coordinates of C. 1.3. Calculate the area of trapezium ABCD (Note: Area of trapezium = ½×(sum of || sides)×height)
diagram below, ABCD is a trapezium, AD||BC and AB⊥BC. The coordinates of D(0;1). The equation of the line BC is 2y-x+4=0. The gradient of AB is -2. The equation of straight line AB is y+2x+2=0. 1.2. E(12;y) is a point on BC produced 1.2.1. Determine the value of y 1.2.2. Given that C is the midpoint of BE, calculate the coordinates of C. 1.3. Calculate the area of trapezium ABCD (Note: Area of trapezium = ½×(sum of || sides)×height)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In the diagram below, ABCD is a trapezium, AD||BC and AB⊥BC. The coordinates of D(0;1). The equation of the line BC is 2y-x+4=0. The gradient of AB is -2. The equation of straight line AB is y+2x+2=0.
1.2. E(12;y) is a point on BC produced
1.2.1. Determine the value of y
1.2.2. Given that C is the midpoint of BE, calculate the coordinates of C.
1.3. Calculate the area of trapezium ABCD
(Note: Area of trapezium = ½×(sum of || sides)×height)
Transcribed Image Text:D(0:1)
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