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dia ty O A Your answers: 0x = TV = Albert B 4/3 4/6 4/6 2/3 Problem Statement: A solid circular shaft with diameter D = 2 in, length L = 36 in is simply-supported at both ends, and further restrained from spinning around x at x=0. The shaft is subjected to a downward uniform distributed load q = 50 lbf/in over 1/3 of the span, centered around the mid-span, in the region x=L/3 to x=2L/3. Downward means in the negative y-direction. Also, torque T = 4000 lbf.in and axial force N = 2000 lbf are applied at x=L. TT = Tmax= £179 Draw the shear and bending moment diagrams, and using that, calculate at x = L/2, y = D/2: • The normal stress , which is the sum of the axial stress N/A plus the bending stress -yM/I. The shear stress due to shear V. The shear stress due to torque T. • Draw Mohr's circle 2D and from it calculate the max. shear stress. Answer tolerance = 2%. Be sure to include units and sign according to the convention shown in the videos and Figures 3-3 and 3-17 in the textbook. Even if a value is zero, it needs units. When using US customary system of units, Webwork only accepts lbf, lbf in, psi, and inches (denoted by "in"); lb means pound mass. *

dia ty O A Your answers: 0x = TV = Albert B 4/3 4/6 4/6 2/3 Problem Statement: A solid circular shaft with diameter D = 2 in, length L = 36 in is simply-supported at both ends, and further restrained from spinning around x at x=0. The shaft is subjected to a downward uniform distributed load q = 50 lbf/in over 1/3 of the span, centered around the mid-span, in the region x=L/3 to x=2L/3. Downward means in the negative y-direction. Also, torque T = 4000 lbf.in and axial force N = 2000 lbf are applied at x=L. TT = Tmax= £179 Draw the shear and bending moment diagrams, and using that, calculate at x = L/2, y = D/2: • The normal stress , which is the sum of the axial stress N/A plus the bending stress -yM/I. The shear stress due to shear V. The shear stress due to torque T. • Draw Mohr's circle 2D and from it calculate the max. shear stress. Answer tolerance = 2%. Be sure to include units and sign according to the convention shown in the videos and Figures 3-3 and 3-17 in the textbook. Even if a value is zero, it needs units. When using US customary system of units, Webwork only accepts lbf, lbf in, psi, and inches (denoted by "in"); lb means pound mass. *

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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dia ry Albert B 4/3 4/6 4/6 4/3 Your answers: 0x = Tv = TT = Tmax= 1² Problem Statement: = A solid circular shaft with diameter D = 2 in, length L 36 in is simply-supported at both ends, and further restrained from spinning around x at x=0. The shaft is subjected to a downward uniform distributed load q 50 lbf/in over 1/3 of the span, centered around the mid-span, in the region x=L/3 to x=2L/3. Downward means in the negative y-direction. Also, torque T = 4000 lbf.in and axial force N = 2000 lbf are applied at x=L. = N Draw the shear and bending moment diagrams, and using that, calculate at x = L/2, y = D/2: • The normal stress , which is the sum of the axial stress N/A plus the bending stress -yM/I. • The shear stress due to shear V. • The shear stress due to torque T. • Draw Mohr's circle 2D and from it calculate the max. shear stress. Answer tolerance = 2%. Be sure to include units and sign according to the convention shown in the videos and Figures 3-3 and 3-17 in the textbook. Even if a value is zero, it needs units. When using US customary system of units, Webwork only accepts lbf, lbf in, psi, and inches (denoted by "in"); lb means pound mass. Note: You can earn partial credit on this problem. 7*
Transcribed Image Text:dia ry Albert B 4/3 4/6 4/6 4/3 Your answers: 0x = Tv = TT = Tmax= 1² Problem Statement: = A solid circular shaft with diameter D = 2 in, length L 36 in is simply-supported at both ends, and further restrained from spinning around x at x=0. The shaft is subjected to a downward uniform distributed load q 50 lbf/in over 1/3 of the span, centered around the mid-span, in the region x=L/3 to x=2L/3. Downward means in the negative y-direction. Also, torque T = 4000 lbf.in and axial force N = 2000 lbf are applied at x=L. = N Draw the shear and bending moment diagrams, and using that, calculate at x = L/2, y = D/2: • The normal stress , which is the sum of the axial stress N/A plus the bending stress -yM/I. • The shear stress due to shear V. • The shear stress due to torque T. • Draw Mohr's circle 2D and from it calculate the max. shear stress. Answer tolerance = 2%. Be sure to include units and sign according to the convention shown in the videos and Figures 3-3 and 3-17 in the textbook. Even if a value is zero, it needs units. When using US customary system of units, Webwork only accepts lbf, lbf in, psi, and inches (denoted by "in"); lb means pound mass. Note: You can earn partial credit on this problem. 7*
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