[D/HD] A different PDE has a full general solution is of the form which of the following is a possible solution consistent with the initial conditions ○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t)) ○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t ○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t u(x, t)=sin(n xx) x e-7n²²t u(x, t0) = sin(6x)+sin(15x) ○ u(x, t) = sin(6 × πx) × e-7×36n²t ○ u(x, t) = sin(15 × xx) × e-7×225²t
[D/HD] A different PDE has a full general solution is of the form which of the following is a possible solution consistent with the initial conditions ○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t)) ○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t ○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t u(x, t)=sin(n xx) x e-7n²²t u(x, t0) = sin(6x)+sin(15x) ○ u(x, t) = sin(6 × πx) × e-7×36n²t ○ u(x, t) = sin(15 × xx) × e-7×225²t
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![[D/HD] A different PDE has a full general solution is of the form
which of the following is a possible solution consistent with the initial conditions
○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t))
○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t
○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t
u(x, t)=sin(n xx) x e-7n²²t
u(x, t0) = sin(6x)+sin(15x)
○ u(x, t) = sin(6 × πx) × e-7×36n²t
○ u(x, t) = sin(15 × xx) × e-7×225²t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe37ebe49-731c-47f9-a49b-3a5f656faaa2%2F8f6ee566-1653-433a-9734-cb7287543394%2F83ked9_processed.png&w=3840&q=75)
Transcribed Image Text:[D/HD] A different PDE has a full general solution is of the form
which of the following is a possible solution consistent with the initial conditions
○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t))
○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t
○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t
u(x, t)=sin(n xx) x e-7n²²t
u(x, t0) = sin(6x)+sin(15x)
○ u(x, t) = sin(6 × πx) × e-7×36n²t
○ u(x, t) = sin(15 × xx) × e-7×225²t
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