dg Use the Chain Rule to evaluate the partial derivative at the point (r, 0) = (2/2, 7 where g(x, y) = 1 x = r sin 0, y = r cos 0. 2x+5y² * dg |(,0)=(2v2,÷)
dg Use the Chain Rule to evaluate the partial derivative at the point (r, 0) = (2/2, 7 where g(x, y) = 1 x = r sin 0, y = r cos 0. 2x+5y² * dg |(,0)=(2v2,÷)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Answer both questions. Thank you.

Transcribed Image Text:Find the maximum rate of change of f(p, q,r) = arctan(pqr) at the point (3, 4, 3).
Answer:

Transcribed Image Text:Use the Chain Rule to evaluate the partial derivative at the point (r, 0) = (2/2, )
where g(x, y) = 2tivē , x = r sin 0, y = r cos 0.
1
= r cos 6.
2x+5y? >
dg
|(1,0)=(2v2,7)
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