20 Devise a reaction scheme to form (S)-2-deuterobutanenitrile from (S)-1-deutero-1-propanol.DHOHstep 1Astep 2DIIHCN Draw the structure for compound A. Be sure to include stereochemistry.Click and drag to start drawing astructure.X:0Ś

The objective of the question is to devise a reaction scheme to form (S)-2-deuterobutanenitrile from (S)-1-deutero-1-propanol and identify the intermediate compound A in the process.In the first step, (S)-1-deutero-1-propanol is converted to compound A. This can be achieved by a reaction with a suitable alkylating agent. The alkylating agent should be such that it introduces a one-carbon unit to the molecule. A suitable alkylating agent for this purpose could be methyl iodide (CH3I). The reaction proceeds via an SN2 mechanism, which results in inversion of stereochemistry. The product of this reaction is (R)-2-deutero-2-butanol, which is compound A.The structure of (R)-2-deutero-2-butanol (compound A) is as follows: The carbon skeleton is a four-carbon chain, with the deutero group (D) and the hydroxyl group (OH) on the second carbon. The methyl group (CH3) introduced by the alkylating agent is on the first carbon. The stereochemistry at the second carbon is R, which means that the priority order of the groups around this carbon, in decreasing order, is OH > D > CH3.In the second step, compound A is converted to (S)-2-deuterobutanenitrile. This can be achieved by a reaction with a suitable nitrile-forming reagent. A suitable reagent for this purpose could be thionyl chloride (SOCl2) followed by cyanide ion (CN-). The reaction with thionyl chloride converts the hydroxyl group into a good leaving group, which is then displaced by the cyanide ion in an SN2 reaction, resulting in inversion of stereochemistry. The product of this reaction is (S)-2-deuterobutanenitrile.The reaction scheme to form (S)-2-deuterobutanenitrile from (S)-1-deutero-1-propanol involves two steps. In the first step, (S)-1-deutero-1-propanol is alkylated with methyl iodide to form (R)-2-deutero-2-butanol (compound A). In the second step, compound A is converted to (S)-2-deuterobutanenitrile by reaction with thionyl chloride followed by cyanide ion.