Deviation boundary% of data points within boundary Probability of any particular data point being outside boundary +20 +36 68.0 95.40 99.70 Csp Tm 8.00M dCi 32.0% 4.60% 0.30%
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- The standard deviation for the high-temperature group is _________ the standard deviation for the low-temperature group. Therefore, an increase in temperature_______________variability in tensile strength.options for first is greater than, smaller than, similar to options for second blank is does not influence or influencesIQ is normally distributed with a mean of 100 and a standard deviation of 15. The middle 50% of IQs fall between what two values? Lower ___ Upper ___Severity million pounds are grown in the US every year. Farm raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 8grams of fat per pound. A random sample of 40 raised trout is selected. The mean fat content for the sample is 31.8 grams per pound, find the probability of observing a sample mean of 31.8 grams of fat per pound or less in a random sample of 40 farm raised trout
- Question Heip How do the requirements for a chi-square test for a variance or standard deviation differ from a z-test or a t-test for a mean? Choose the correct answer below. OA A chi-square test can only be used when the population has a normal distribution. On the other hand, a z-test or a t-test can only be used when the sample size is at least 30. O B. A chi-square test can only be used when the population has a normal distribution. On the other hand, a z-test or a t-test can be used when either the population has a normal distribution or the sample size is at least 30. O C. Az-test or a t-test can only be used when the population has a normal distribution. On the other hand, a chi-square test can be used when either the population has a normal distribution or the sample size is at least 30. O D. Az-test or a t-test can only be used when the population has a normal distribution. On the other hand, a chi-square test can only be used when the sample size is at least 30. Click to…ANOVA How to write hypotheses for ANOVA How is variance parted in ANOVA? Between Withinnormal distrubtion with mean 8 and standard daviation 1 find the 15TH pwecwntile marks of this data set
- GMAT scores are approximately normally distributed with a mean of 547 and a standard deviation of 95. Estimate the percentage of scores that were(a) between 452 and 642. ________%(b) above 832._________ %(c) below 452. ___________%(d) between 357 and 642. ___________% Answer the blanks.Assuming variance > 1, which of the following must be true? The sample variance is calculated based on the sample size rather than the degrees of freedom The data are normally distributed Standard deviation < variance The model will explain more than 50% of the variance of the dependent variableThe ___________ is a weighted average of the Standard Deviations of the conditions of an IV in an independent samples t-test. Pooled estimate of the Standard deviation Standard deviation of the difference Population Standard deviation Standard error of the difference
- mining Time: 16 minutes, 43 seconds. stion Completion Status: Close Window A Moving to another question will save this response. Question 1 of 5 estion 1 4 points Save Answ For a certain medicine, the time it takes before the patient experiences effects is normally distributed with a mean of 48 minutes and a standard deviation of 8 minutes. What proportion of patients wait less than 56.4 miniutes to experience effects? Enter your answer as a decimal (for example 95 not 95%), rounded to 4 decimal places A Moving to another question will save this response. Question 1 of 5 Close Window PrtSc SysRa Pause Break Scr Lk Insert Delete - Backsoace RExcessive fertilizer and surface runoff can result in heavy phosphorus concentrations and reduced oxygen levels in lakes and ponds. This can lead to die-off of insects, fish, an increase in algae, and overall reduced health of the ecosystem. With the increase in algae, you are concerned about the amount of dissolved oxygen (DO). You measure the average DO levels in randomly sampled lakes in two different types (urban and rural) at the same time of year. Conduct a hypothesis test at 5% level of significance. Is there evidence to suggest that the average DO levels are significantly higher in lakes found in rural areas when compared to lakes in more urban areas? Use the table below. What is the test statistic?nvestigate 12 temperature measurements are made in a laboratory over a period of time and the following values are obtained: 46,45,45,47,48,49,50,52,51,51,14,36 Use Chauvenet's criterion to identify any outliers in the data which should be rejected. Don't use the chauvenets table. Use the normal distribution table. es/standard-normal-table 0.06 0.07 0.08 Z 0.00 0.0180 0.0120 0.0160 0.0199 0.0239 0.0279 0.0319 0.0000 0.0040 0.0398 0.0438 0.0478 0.0517 0.0557 0.0596 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 = 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 20 1.9 2.0 2.1 2.2 2.3 74 2.4 2.5 2.6 24 2.7 2.8 2.9 3.0 3.1 = Ee 0.04 0.05 0.02 02 0.03 0.1179 0.1217 0.1255 0.1293 0.1331 0.1368 0.1554 0.1591 0.1628 0.1664 0.1700 0.1736 3.5 3.6 3.7 3.8 0.0793 0.0832 0.0871 0.0910 0.0948 0.0987 0.1026 0.10 1480 0.1517 0.1879 0.1915 0.19502019 0.2054 0.2088 0.2123 0.2157 0.2190 0.2224 0.2422 0.2454 0.2486 0.2517 0.2549 0.1985 0.2324 0.2257 0.2293 0.2580 0.2611 0.2642 0.2389 Amor P7704 0.2764 0.2794 0.2823 0.2852…
