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Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the force in each member of the pin-connected truss. AE is constant. Use force method

Transcribed Image Text:**Problem 9–26**
**Objective:** Determine the force in each member of the pin-connected truss. The modulus of elasticity (AE) is constant.
**Diagram Explanation:**
The diagram illustrates a symmetrical pin-connected truss in the shape of a diamond or square positioned diagonally. The key elements are:
- **Points:** A, B, C, and D are connected by truss members. The truss is symmetric about its vertical and horizontal axes.
- **Distances:** Each side of the square (AB, BC, CD, and DA) is 3 feet in length.
- **Forces:**
- A force of 2 kips (k) acts to the left on point A.
- A force of 2 kips (k) acts to the right on point C.
**Truss Members:**
The truss consists of the following members:
- Horizontal members: AC
- Vertical members: BD
- Diagonal members: AD and BC
The task involves calculating the forces within these members, considering the symmetry and external loads applied at points A and C.
**Instructions for Students:**
Utilize methods such as the joint method or section method to resolve the forces in each member of the truss, assuming equilibrium conditions (ΣF = 0). Recognize that symmetry may simplify calculations, and ensure to account for tension and compression forces.
**Note:**
When calculating, take into consideration the constant AE for uniformity in analysis.
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