Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) n2 %3D + 2n lim a = n- 00

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem Statement:**

Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)

\[ a_n = \frac{n^2}{\sqrt{n^3 + 2n}} \]

\[ \lim_{{n \to \infty}} a_n = \]

**Instructions:**

You are given a sequence defined by the formula \( a_n = \frac{n^2}{\sqrt{n^3 + 2n}} \). Your task is to evaluate the limit of the sequence as \( n \) approaches infinity. Determine if the sequence converges to a specific value or if it diverges. If it converges, provide the limiting value. If the limit does not exist, indicate this by entering "DNE" (Does Not Exist). 

**Note:**

This problem requires understanding the behavior of sequences and limits as they approach infinity, often involving techniques like simplifying the expression or using L'Hopital's Rule if applicable.
Transcribed Image Text:**Problem Statement:** Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) \[ a_n = \frac{n^2}{\sqrt{n^3 + 2n}} \] \[ \lim_{{n \to \infty}} a_n = \] **Instructions:** You are given a sequence defined by the formula \( a_n = \frac{n^2}{\sqrt{n^3 + 2n}} \). Your task is to evaluate the limit of the sequence as \( n \) approaches infinity. Determine if the sequence converges to a specific value or if it diverges. If it converges, provide the limiting value. If the limit does not exist, indicate this by entering "DNE" (Does Not Exist). **Note:** This problem requires understanding the behavior of sequences and limits as they approach infinity, often involving techniques like simplifying the expression or using L'Hopital's Rule if applicable.
Expert Solution
Step 1

The given sequence is an=n2n3+2n

Step 2

Now, 

a1=13a2=23>a1a3=933>a2

and so on.

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