Determine whether the sequence converges or diverges. If it converges, find the limit. (2n-1)!] a) (2n+1)!] 2" sin n b) a, = 3"

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Determine whether the sequence converges or diverges. If it converges, find the limit.**

a) \[\left\{ \frac{(2n-1)!}{(2n+1)!} \right\}\]

b) \[a_n = \frac{2^n \sin n}{3^n}\]

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**Explanation:**

The problem poses two sequences for analysis to determine their convergence or divergence. If a sequence converges, the task is to find the limit of that sequence.

### a) \[\left\{ \frac{(2n-1)!}{(2n+1)!} \right\}\]

This sequence involves the factorials of the terms \(2n-1\) and \(2n+1\), which present a more complex factorial relationship that may potentially simplify when factoring terms.

### b) \[a_n = \frac{2^n \sin n}{3^n}\]

This sequence involves an exponential term in the numerator and an exponential term in the denominator, along with a sinusoidal function. The behavior of the sine function and the ratio of the exponential terms will dictate the convergence or divergence of the sequence.
Transcribed Image Text:**Determine whether the sequence converges or diverges. If it converges, find the limit.** a) \[\left\{ \frac{(2n-1)!}{(2n+1)!} \right\}\] b) \[a_n = \frac{2^n \sin n}{3^n}\] --- **Explanation:** The problem poses two sequences for analysis to determine their convergence or divergence. If a sequence converges, the task is to find the limit of that sequence. ### a) \[\left\{ \frac{(2n-1)!}{(2n+1)!} \right\}\] This sequence involves the factorials of the terms \(2n-1\) and \(2n+1\), which present a more complex factorial relationship that may potentially simplify when factoring terms. ### b) \[a_n = \frac{2^n \sin n}{3^n}\] This sequence involves an exponential term in the numerator and an exponential term in the denominator, along with a sinusoidal function. The behavior of the sine function and the ratio of the exponential terms will dictate the convergence or divergence of the sequence.
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