Determine whether the graph could represent a variable with a normal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation. Determine whether the graph couldrepresent a variable with a normaldistribution. Explain your reasoning. Ifthe graph appears to represent a normaldistribution, estimate the mean andstandard deviation.s-3-5is o =Could the graph represent a variable with a normal distribution? Select the correctchoice below and, if necessary, fill in the answer boxes to complete your choice.O A. No, because the graph is symmetric but it is not bell shaped.B. No, because the graph is not continuous.C. No, because the graph is bell shaped but it is not symmetric.D. Yes. The estimated mean is =μ0.(Round to one decimal place as needed.)-1and the estimated standard deviation

The graph has two peaks which are symmetric. But we know that in normal distribution there is only…

Answered: Determine whether the graph could…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

Determine whether the graph could represent a variable with a normal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution