Determine whether the following discrete-time signals are periodic, and, if so, state the fundamental period, No. a. a[n] = 0.5 cos("/6n+"/3) b. b[n] = E=-0 8[n – 6k] c. c[n] = 0.5 sin(3n)
Determine whether the following discrete-time signals are periodic, and, if so, state the fundamental period, No. a. a[n] = 0.5 cos("/6n+"/3) b. b[n] = E=-0 8[n – 6k] c. c[n] = 0.5 sin(3n)
Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
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![Determine whether the following discrete-time signals are periodic, and, if so, state the
fundamental period, No.
a. a[n] = 0.5 cos("/6n+"/3)
b. b[n] = E=-0 8[n – 6k]
c. c[n] = 0.5 sin(3n)
A continuous valued 9 kHz sinusoid is sampled at a rate of 48k samples/sec to produce a
sequence x[n]. Determine if the sequence is periodic and if so, what is No, the period.
Let x[n]
0.8"u[n] and y[n] = (-0.8)"u[n]
Plot x[n] and y[n] for n = -2, -1, ... , 4, 5
b. Find En=-ox[n]
Find En=-o y[n]
а.
c.
Find the energy in x[n]
Find the energy in y[n]
d.
е.
A discrete time system is described by the difference equation y[n] :
x[n] is the input and y[n] is the output. Plot y[n] for:
х[п] — x[п — 1], where
а.
x[n] = 8[n]
b. x[n] = u[n] - [n – 3]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11657d80-0b9a-4a9b-9635-8d2c2856a255%2F6a1139e7-9d8e-4d11-8b0a-c316254c0fdb%2Fi3rwodj_processed.png&w=3840&q=75)
Transcribed Image Text:Determine whether the following discrete-time signals are periodic, and, if so, state the
fundamental period, No.
a. a[n] = 0.5 cos("/6n+"/3)
b. b[n] = E=-0 8[n – 6k]
c. c[n] = 0.5 sin(3n)
A continuous valued 9 kHz sinusoid is sampled at a rate of 48k samples/sec to produce a
sequence x[n]. Determine if the sequence is periodic and if so, what is No, the period.
Let x[n]
0.8"u[n] and y[n] = (-0.8)"u[n]
Plot x[n] and y[n] for n = -2, -1, ... , 4, 5
b. Find En=-ox[n]
Find En=-o y[n]
а.
c.
Find the energy in x[n]
Find the energy in y[n]
d.
е.
A discrete time system is described by the difference equation y[n] :
x[n] is the input and y[n] is the output. Plot y[n] for:
х[п] — x[п — 1], where
а.
x[n] = 8[n]
b. x[n] = u[n] - [n – 3]
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