Determine whether the block shown is in equilibrium and find the magnitude and direction of the friction force when 8 = 30° and P= 45 lb. Given: μs = 0.30 and μk = 0.20. 250 lb The block is not in equilibrium and moves down. True The magnitude and direction of friction force is 86.03 lb 7
Determine whether the block shown is in equilibrium and find the magnitude and direction of the friction force when 8 = 30° and P= 45 lb. Given: μs = 0.30 and μk = 0.20. 250 lb The block is not in equilibrium and moves down. True The magnitude and direction of friction force is 86.03 lb 7
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Determine whether the block shown is in equilibrium and find the magnitude and direction of the friction force when 0 = 30° and P=
45 lb. Given: μs = 0.30 and k = 0.20.
250 lb
The block is not in equilibrium and moves down.
True
The magnitude and direction of friction force is
86.03 lb 7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96023f4d-6281-4c81-803e-adfe3e4197d6%2F2c6d8d27-888e-49aa-8df3-6e6b89442972%2Frybeshj_processed.png&w=3840&q=75)
Transcribed Image Text:Determine whether the block shown is in equilibrium and find the magnitude and direction of the friction force when 0 = 30° and P=
45 lb. Given: μs = 0.30 and k = 0.20.
250 lb
The block is not in equilibrium and moves down.
True
The magnitude and direction of friction force is
86.03 lb 7
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This is still the wrong answer for McGraw Hill. Each answer I try is wrong, so not sure if I'm doing the problem wrong. It's not 71.70 or 71.07.
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71.7 is being marked wrong in McGraw Hill homework. I thought I had done it right with putting 86.03 but that is wrong also. I'm not trying to just find the answer, trying to find how to do this. Could there be a different number than 71.7? Where does the μk=0.20 come into the equation?
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