Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![**Instructions:**
Determine whether or not the given function is one-to-one and, if so, find the inverse: \( f(x) = \frac{7}{2} \cos(x) \) with \( x \in \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \).
**Options:**
a) \( f^{-1}(x) = \sec \left( \frac{2}{7} x \right) \)
b) Not one-to-one
c) \( f^{-1}(x) = \frac{7}{2} \sin(x) \)
d) \( f^{-1}(x) = \frac{7}{2} \sec(x) \)
e) \( f^{-1}(x) = \arccos \left( \frac{2}{7} x \right) \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c03d17e-03c0-44bf-860a-ef4a718bf31e%2F455b8359-ee60-4975-bfe5-3e2e5c13f331%2Foclfmgs_processed.png&w=3840&q=75)
Transcribed Image Text:**Instructions:**
Determine whether or not the given function is one-to-one and, if so, find the inverse: \( f(x) = \frac{7}{2} \cos(x) \) with \( x \in \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \).
**Options:**
a) \( f^{-1}(x) = \sec \left( \frac{2}{7} x \right) \)
b) Not one-to-one
c) \( f^{-1}(x) = \frac{7}{2} \sin(x) \)
d) \( f^{-1}(x) = \frac{7}{2} \sec(x) \)
e) \( f^{-1}(x) = \arccos \left( \frac{2}{7} x \right) \)
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