Determine whether following series convergent or divergent. Indicate the test you are using. If you need to find a limit of a rational expression, you may divide by the highest power and find the limit. n=1 n=1 00 n=1 1 n(ln(n + 1))² 2n+1 (n + 2)! 3n² + 2n-1 (n + 2)² csc²n (2n-1) (√n)" n=1 (n + 3)²

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine whether following series convergent or divergent. Indicate the test you are using. If you need to
find a limit of a rational expression, you may divide by the highest power and find the limit.
n=1
n=1
00
n=1
1
n(ln(n + 1))²
2n+1
(n + 2)!
3n² + 2n-1
(n + 2)²
csc²n
(2n-1)
(√n)"
n=1 (n + 3)²
Transcribed Image Text:Determine whether following series convergent or divergent. Indicate the test you are using. If you need to find a limit of a rational expression, you may divide by the highest power and find the limit. n=1 n=1 00 n=1 1 n(ln(n + 1))² 2n+1 (n + 2)! 3n² + 2n-1 (n + 2)² csc²n (2n-1) (√n)" n=1 (n + 3)²
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