Determine the work (in Joules) done if the force of friction is 20 N and the applied force of the man is 100 N. Assume the ice has a mass of 10 kg, the person pulls on the ice with a force of 100 N at a 45 degree angle, and the ice moves 1 meter.

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A: Given data:  Two electrons situated at a distance (r) = 10 cm Fg = gravitational force Fe =…

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A: Given, Charge at the top of the cloud, q1 = 45.0 C charge at the bottom of the cloud, q2 = -45.0 C…

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A: Charge on proton = e = 1.6 × 10-19C  Side of equilateral triangle =a= 2.00 × 10-15 m  Work done in…

Q: Q4. Consider the circuit shown in Fig. P4.25. Suppose that vs(t) = 12√/Zcos(3t) V and C=1/6 F. Find…

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Q: in cm-1)

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Q: and F represents gravitational and electrostatic force respectively between electrons situated at a…

A: Given value--- distance between electron = 10 cm. We have to find--- the ratio of Fg / Fe ?

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A: Electric field, electron move from  ( x0,0,0 ) to ( 0,0,z0 ).

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A: Given data: Refractive index of the crown glass n = 1.52 speed of light v =3×108 m/s

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Q: How would you rearrange that equation for m_0

A: R = V(L/D)Cln (11-mf/mo)DCRVL= ln(11-mf/m0)11-mf/m0 = eDCRVL