Determine the voltage drop (in volts) across the 3 Ω resistor in the circuit below.

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Determine the voltage drop (in volts) across the 3 Ω resistor in the circuit below.

### Figure P18.22: Electrical Circuit Diagram

**Description:**

This diagram illustrates a simple electrical circuit containing a voltage source and three resistors. 

**Components:**

1. **Voltage Source:**
   - The circuit includes a 12V battery, positioned on the left side of the circuit.

2. **Resistors:**
   - **Resistor 1 (R1):** 6.0Ω
   - **Resistor 2 (R2):** 9.0Ω
   - **Resistor 3 (R3):** 3.0Ω
   - Resistors R1 and R2 are arranged in parallel at the top of the circuit.
   - Resistor R3 is in series with the parallel combination of R1 and R2.

**Configuration:**

- The circuit starts at the negative terminal of the 12V battery and flows through resistor R3.
- From R3, the current splits to flow through either R1 or R2, which are arranged in a parallel configuration.
- The current then recombines before returning to the positive terminal of the battery.

**Analysis:**

- **Series and Parallel Configuration:**
  - The total resistance of the circuit can be calculated by first finding the equivalent resistance of the parallel resistors (R1 and R2) and then adding the resistance of R3.
  
- **Calculating Equivalent Resistance for Parallel Resistors:**
  - \[ \frac{1}{R_{\text{eq}}} = \frac{1}{R1} + \frac{1}{R2} = \frac{1}{6.0} + \frac{1}{9.0} \]
  
- **Total Circuit Resistance (R_total):**
  - \[ R_{\text{total}} = R_{\text{eq}} + R3 \]

This setup is ideal for analyzing the behavior of resistors in series and parallel, understanding voltage drops, and calculating total current using Ohm's Law.
Transcribed Image Text:### Figure P18.22: Electrical Circuit Diagram **Description:** This diagram illustrates a simple electrical circuit containing a voltage source and three resistors. **Components:** 1. **Voltage Source:** - The circuit includes a 12V battery, positioned on the left side of the circuit. 2. **Resistors:** - **Resistor 1 (R1):** 6.0Ω - **Resistor 2 (R2):** 9.0Ω - **Resistor 3 (R3):** 3.0Ω - Resistors R1 and R2 are arranged in parallel at the top of the circuit. - Resistor R3 is in series with the parallel combination of R1 and R2. **Configuration:** - The circuit starts at the negative terminal of the 12V battery and flows through resistor R3. - From R3, the current splits to flow through either R1 or R2, which are arranged in a parallel configuration. - The current then recombines before returning to the positive terminal of the battery. **Analysis:** - **Series and Parallel Configuration:** - The total resistance of the circuit can be calculated by first finding the equivalent resistance of the parallel resistors (R1 and R2) and then adding the resistance of R3. - **Calculating Equivalent Resistance for Parallel Resistors:** - \[ \frac{1}{R_{\text{eq}}} = \frac{1}{R1} + \frac{1}{R2} = \frac{1}{6.0} + \frac{1}{9.0} \] - **Total Circuit Resistance (R_total):** - \[ R_{\text{total}} = R_{\text{eq}} + R3 \] This setup is ideal for analyzing the behavior of resistors in series and parallel, understanding voltage drops, and calculating total current using Ohm's Law.
Expert Solution
Step 1

From the circuit,  6 Ω resistor and 9 Ω resistor connected in parallel.

so that, equivalent resistance is as follows;

1Req=1R1+1R2                                             1)1Req=16+19Req=3.6 Ω

 

 

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