Determine the values of p for which the series A. PE B. PE ME n=2 C. PE D. pe (-0,2) E. The series will converge for any value of p. √4n³ + 3n np (ln(n))² will converge.

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A: Given ∑n=1∞an=8∑n=1∞bn=−2Also, a1=9,b1=1

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