Determine the value of Ksp for Zn3(PO4)2 by constructing an ICE table, writing the solubility constant expression, and solving the expression. Complete Parts 1-2 before submitting your answer. NEXT > The molar solubility of Zn3(PO4)2 is 5.6 x 10-5 M at a certain temperature. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products at this temperature. Initial (M) Change (M) Equilibrium (M) 1.7 x 10-13 -1.12 x 10-5 0 1.9 x 10-8 1.68 x 10-5 Zn3(PO4)2(S) 5.6 x 10-5 5.9 x 10-20 -1.68 x 10-5 -5.6 x 10-5 -5.6 x 10-20 3 Zn²+ (aq) 1.12 x 10-4 2 -1.7 x 10-13 -1.12 x 10-4 -1.9 x 10-8 + 2 PO4³-(aq) 1.68 x 10-4 -5.9 x 10-20 RESET -1.68 x 10-4 1.12 x 10-5
Determine the value of Ksp for Zn3(PO4)2 by constructing an ICE table, writing the solubility constant expression, and solving the expression. Complete Parts 1-2 before submitting your answer. NEXT > The molar solubility of Zn3(PO4)2 is 5.6 x 10-5 M at a certain temperature. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products at this temperature. Initial (M) Change (M) Equilibrium (M) 1.7 x 10-13 -1.12 x 10-5 0 1.9 x 10-8 1.68 x 10-5 Zn3(PO4)2(S) 5.6 x 10-5 5.9 x 10-20 -1.68 x 10-5 -5.6 x 10-5 -5.6 x 10-20 3 Zn²+ (aq) 1.12 x 10-4 2 -1.7 x 10-13 -1.12 x 10-4 -1.9 x 10-8 + 2 PO4³-(aq) 1.68 x 10-4 -5.9 x 10-20 RESET -1.68 x 10-4 1.12 x 10-5
General Chemistry - Standalone book (MindTap Course List)
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Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter17: Solubility And Complex-ion Equilibria
Section: Chapter Questions
Problem 17.98QP: A saturated solution of lead iodate in pure water has an iodate-ion concentration of 8.0 105 M. a...
Related questions
Question
![Determine the value of Ksp for Zn3(PO4)2 by constructing an ICE table, writing the
solubility constant expression, and solving the expression. Complete Parts 1-2 before
submitting your answer.
NEXT >
The molar solubility of Zn3(PO4)2 is 5.6 × 10-5 M at a certain temperature. Fill in the ICE table with the
appropriate value for each involved species to determine concentrations of all reactants and products at
this temperature.
Initial (M)
Change (M)
Equilibrium (M)
1.7 x 10-13
-1.12 x 10-5
0
1.9 x 10¹⁹
1.68 x 10-5
1
Zn3(PO4)2(S)
5.6 x 10-5
5.9 x 10-20
-1.68 x 10-5
-5.6 x 10-5
-5.6 x 10-2⁰
3 Zn²+ (aq)
1.12 x 10-4
2
-1.7 x 10-13
-1.12 x 10-4
-1.9 × 10-⁹
+
1.68 x 10-4
-5.9 x 10-20
2 PO4³-(aq)
RESET
-1.68 x 10-4
1.12 x 10-5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53fad175-5b35-4951-b14a-e374468693f0%2F2f1a94c6-0c06-419e-be22-7a9d7bc6a2ba%2Fxgu9sg_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the value of Ksp for Zn3(PO4)2 by constructing an ICE table, writing the
solubility constant expression, and solving the expression. Complete Parts 1-2 before
submitting your answer.
NEXT >
The molar solubility of Zn3(PO4)2 is 5.6 × 10-5 M at a certain temperature. Fill in the ICE table with the
appropriate value for each involved species to determine concentrations of all reactants and products at
this temperature.
Initial (M)
Change (M)
Equilibrium (M)
1.7 x 10-13
-1.12 x 10-5
0
1.9 x 10¹⁹
1.68 x 10-5
1
Zn3(PO4)2(S)
5.6 x 10-5
5.9 x 10-20
-1.68 x 10-5
-5.6 x 10-5
-5.6 x 10-2⁰
3 Zn²+ (aq)
1.12 x 10-4
2
-1.7 x 10-13
-1.12 x 10-4
-1.9 × 10-⁹
+
1.68 x 10-4
-5.9 x 10-20
2 PO4³-(aq)
RESET
-1.68 x 10-4
1.12 x 10-5
![Determine the value of Ksp for Zn³(PO4)2 by constructing an ICE table, writing the
solubility constant expression, and solving the expression. Complete Parts 1-2 before
submitting your answer.
PREV
Using the values from the ICE table, construct the expression for the solubility constant. Each reaction
participant must be represented by one tile. Do not combine terms Once the expression is constructed,
solve for Ksp.
[0]
[1.9 × 10-9]
[1.12 x 10-5]
[5.6 x 10-]
5.9 x 10-20
[1.68 x 10-⁹]
Ksp
1
[1.12 x 10-4]
[1.7 x 10-¹³1²
[1.12 x 10-1²
[1.68 x 10-4]
[1.9 × 10-1²
2.6 x 10-³
[5.6 x 10-51²
3.5x 10-39
=
3.8 x 10-4
2
[1.12 x 10-41²
[1.7 x 10-1³]³
[1.68 x 10-41³
[1.9 x 10-1³
✓ RESET
[1.7 x 10-¹³]
2.1 x 10-58](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53fad175-5b35-4951-b14a-e374468693f0%2F2f1a94c6-0c06-419e-be22-7a9d7bc6a2ba%2F4wvuhdd_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the value of Ksp for Zn³(PO4)2 by constructing an ICE table, writing the
solubility constant expression, and solving the expression. Complete Parts 1-2 before
submitting your answer.
PREV
Using the values from the ICE table, construct the expression for the solubility constant. Each reaction
participant must be represented by one tile. Do not combine terms Once the expression is constructed,
solve for Ksp.
[0]
[1.9 × 10-9]
[1.12 x 10-5]
[5.6 x 10-]
5.9 x 10-20
[1.68 x 10-⁹]
Ksp
1
[1.12 x 10-4]
[1.7 x 10-¹³1²
[1.12 x 10-1²
[1.68 x 10-4]
[1.9 × 10-1²
2.6 x 10-³
[5.6 x 10-51²
3.5x 10-39
=
3.8 x 10-4
2
[1.12 x 10-41²
[1.7 x 10-1³]³
[1.68 x 10-41³
[1.9 x 10-1³
✓ RESET
[1.7 x 10-¹³]
2.1 x 10-58
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