Determine the value of f"(1) when f(x) = 3 ln (2x + 1). 1. ƒ" (1) 2. f" (1) 13. ƒ" (1) 5. ƒ"(1) = 6. ƒ"(1) = 4. f"(1) = −4 -4 = 4 = 813 = I 4 3

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A: Given logb(N4)=8logb(1N)=?That can be written as lobb(N-1)

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Q: Determine the value of f"(1) when f(x) 3 ln (2x + 1). 1. f"(1) = 813 5. f"(1) = = 2. f" (1) 3. f"(1)…

A:

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