Determine the value of c such that the function is a probability mass function. h(x) = cx(x-1), x= 6, 8, 10, 12 C= (Simplify your answer.)
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- please helpLet X = daily number of bag of rice a farmer harvest. The farmer modeled X and got the following probability mass function. X 0 1 2 3 4 P(X=x) 0.1 0.4 0.25 0.15 0.10 a. The probability that the farmer will harvest 5 bags of rice today is? b. The probability that the farmer will harvest at least 2 bags of rice today? c. The amount of bags of rice the farmer harvest for a day on the average is? d. If the farmer gets $300 per bag, what is the farmer's average daily earnings? e. What is the variance of X?ACTIVITY 2: COMPUTE ME Direction: Determine each of the following areas and show this graphically. Use probability notation to your final answer. Write your answer on the space provided. 1.above z=1.46 2.below z=-0.58 3. between z=-1.8 and z=-1.95 4. Between z-0.76 and z=2.88 5. Between z=D-0.92 and z-1.75
- Show work for every step. Two types of customers (Preferred and Regular) call a service center. Preferred customers call with rate 3 per hour, and Regular customers call with rate 5 per hour. The interarrival times of the calls for each customer type are exponentially distributed. If the call center opens at 8:00 AM, what is the probability that the first call (regardless of customers type who calls) is received before 8:15 AM?Answers for a, b and c(Revision.) Let X = Wo.5 + 0.5W1 – 2W2 – W3, where (W1, t > 0) is standard BM. Find the expectation E(X²).
- Thank you in Advance for quick response. Best,Use Bayes' theorem or a tree diagram to calculate the indicated probability. Round your answer to four decimal places. Y1, Y2, Y3 form a partition of S. P(X | Y,) = 0.8, P(X | Y2) = 0.2, P(X | Y3) = 0.5, P(Y,) = 0.2, P(Y2) = 0.4. Find P(Y1| X).Use Bayes' theorem or a tree diagram to calculate the indicated probability. Round your answer to four decimal places. Y1, Y2, Y3 form a partition of S. P(X | Y1) = 0.5, P(X | Y2) = 0.1, P(X | Y3) = 0.8, P(Y,) = 0.1, P(Y2) = 0.4. Find P(Y1 | X). %3D P(Y1 | X) =