Determine the value of C P(-0.82 ≤ z = C) = 0.7810
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![### Determine the Value of C
Given the problem:
\[ P(-0.82 \leq z \leq C) = 0.7810 \]
In this scenario, we are asked to find the value of \( C \) for which the probability that the z-score \( z \) lies between -0.82 and \( C \) equals 0.7810.
To solve this problem:
1. **Understanding the Probability and z-Scores:**
- The probability \( P(-0.82 \leq z \leq C) = 0.7810 \) signifies that the area under the standard normal curve between \( z = -0.82 \) and \( z = C \) is 0.7810.
2. **Using Standard Normal Distribution Tables or a z-Score Calculator:**
- First, we determine the cumulative probability associated with \( z = -0.82 \).
- Next, we add 0.7810 to this probability to determine the cumulative probability corresponding to \( z = C \).
- Finally, we find the z-score corresponding to this cumulative probability.
This problem is a typical example in statistics where we need to locate a specific z-score corresponding to a given probability, utilizing the standard normal distribution table or statistical software for accurate results.
Below provided is the handwritten transcription of the problem:
**Problem Statement:**
\[ \text{Determine the value of } C \]
\[ P(-0.82 \leq z \leq C) = 0.7810 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2561c632-65dd-4d60-9cc7-c4695e3617a7%2Fdc7093da-3e66-4311-b733-3bec2d7a5a01%2Fr3x67au_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Determine the Value of C
Given the problem:
\[ P(-0.82 \leq z \leq C) = 0.7810 \]
In this scenario, we are asked to find the value of \( C \) for which the probability that the z-score \( z \) lies between -0.82 and \( C \) equals 0.7810.
To solve this problem:
1. **Understanding the Probability and z-Scores:**
- The probability \( P(-0.82 \leq z \leq C) = 0.7810 \) signifies that the area under the standard normal curve between \( z = -0.82 \) and \( z = C \) is 0.7810.
2. **Using Standard Normal Distribution Tables or a z-Score Calculator:**
- First, we determine the cumulative probability associated with \( z = -0.82 \).
- Next, we add 0.7810 to this probability to determine the cumulative probability corresponding to \( z = C \).
- Finally, we find the z-score corresponding to this cumulative probability.
This problem is a typical example in statistics where we need to locate a specific z-score corresponding to a given probability, utilizing the standard normal distribution table or statistical software for accurate results.
Below provided is the handwritten transcription of the problem:
**Problem Statement:**
\[ \text{Determine the value of } C \]
\[ P(-0.82 \leq z \leq C) = 0.7810 \]
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