Determine the suitable lapping on an auto-transformer starter for an induction motor required to start the motor with 40 per cent of full-load torque. The short-circuit current of the motor is 5 times the full load current and full-land slip is 0.035. Also deternmine the current drawn from the mains as a fraction of full-load current.

Determine the suitable lapping on an auto-transformer starter for an induction motor required to start the motor with 40 per cent of full-load torque. The short-circuit current of the motor is 5 times the full load current and full-land slip is 0.035. Also deternmine the current drawn from the mains as a fraction of full-load current.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Calculate the CMRR (in dB) for the circuit measurements of Va = 1 mV,V, = 120 mV,Vc = 1 mV, and 20 μν. %3D Vo
When an induction motor is started directly from the line, the starting torque is 1.75 times full load torque. What will the motor starting torque in terms of full-load value, when the machine is started by the Y-A method? Answer: 1.0103 TFL
8) No handwritten, only typing...
f 121. A 400 V shunt motor takes a current of 120 A and runs at 1000 rpm. The armature resistance is 0.2 ohm. Calculate the speed with the same torque if magnetic flux is reduced to 80% of the initial. A. 1230 rpm B. 1240 rpm C. 1260 rpm D. 1250 rpm
l7 answer 4 5 6
Question The power input to a 500 V, 50 Hz, 6-pole, 3-phase induction motor running at 975 RPM is 40 kW. The total stator losses are 1 kW. If the total friction and windage losses are 2.025 kW, then the efficiency is %
When an induction motor is started directly from the line, the starting torque is 1.75 times full load torque. What will the motor starting torque in terms of full-load value, when the machine is started by the Y-A method? Answer: 1.0103 TFL
Define slip in an induction motor.
A 400 volts 4 pole 50 Hz three phase star connected induction motor has r¡=0,x1=x2=1 Q, r;=0.42, xm= 500 Q. The induction motor is fed from i. A constant voltage source of 231 volts per phase and ii. A constant current source of 28 A. For both the cases calculate the slip at which maximum torque occurs and the starting and maximum torques.
Determine the starting torque of a three-phase induction motor in terms of full load torque when started by means of: 1. Star delta starter; 2. An auto-transformer starter with 50% tapings. The motor draws a starting current of 5 times the full load current when started direct-on line. The full load slip is 4 percent.
At 1170 rpm, a three-phase IM generates 4 kilowatt. It is a 6 pole, 60 Hz transformer. Friction and windage losses aren't taken into account. If the stator losses are 250 w, the stator input power will be? * Your answer The gross power of a single phase induction motor absorbed by the backward and the forward fields are 30 w and 160 w respectively. the motor runs at speed of 950 rpm. the no-load frictional losses are 70 w. if the number of poles are 6 and the supply frequency is 50 Hz, the shaft torque will be: * 0.583 0.564 0.578 none of the mentioned 0.835 0.538