Determine the smallest coefficient of static friction at both A and B needed to hold the uniform 100-lb bar in equilibrium. Neglect the thickness of the Take ua = pug = µ. O A) t, £F, = 0; FA + FR = NB bar. 12 + NA 13 3 ft B) +1£F, = 0: NR + FR - 100 = 0 12 I, EF, = 0; F + FR 13 - NR = 0 13 13 ft 5 ft D) (+EMA = 0; NR (13) – 100 |(8) = 0 13 A Na + F) 12 + NB 13 O E) +1EF, = 0; 100 = 0 reaction forces at A and B; NA and NR friction forces at A and B; FA and F. Which equation is WRONG?

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Determine the smallest coefficient of static friction at both
A and B needed to hold the uniform 100-lb bar
in equilibrium. Neglect the
Take ua = µB = µ.
Fa + F) - Na A)
A)
5,EF, = 0;
= NB
13
thickness of the bar.
13
3 ft
B)
+12F, = 0;
NB + FR
- 100 = 0
+
13
13
B
5EF, = 0;
FA + FB
NB
= 0
13
13 ft
5 ft
12
(8) = 0
13
D)
S+EMA = 0; NB (13) - 100
+12F, = 0;
NA + Fg
13
12
+ NB
13
100 = 0
reaction forces at A and B; NA and N
В
friction forces at A and B;
A
and F.
В
Which equation is WRONG?
Transcribed Image Text:Determine the smallest coefficient of static friction at both A and B needed to hold the uniform 100-lb bar in equilibrium. Neglect the Take ua = µB = µ. Fa + F) - Na A) A) 5,EF, = 0; = NB 13 thickness of the bar. 13 3 ft B) +12F, = 0; NB + FR - 100 = 0 + 13 13 B 5EF, = 0; FA + FB NB = 0 13 13 ft 5 ft 12 (8) = 0 13 D) S+EMA = 0; NB (13) - 100 +12F, = 0; NA + Fg 13 12 + NB 13 100 = 0 reaction forces at A and B; NA and N В friction forces at A and B; A and F. В Which equation is WRONG?
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