Determine the reactions of the given beam using moment distribution method. w = = 25 kN/m, P₁ = 25 kN, and P₂ = 25 kN RA RB _ || MB Rc _|| = W Numerical answer in 4 decimal places and positive values only: = 8 m 21 B 2m P₁ I 2m P2 2m C kN (Downward) kN-m kN (Upward) kN (Upward)
Determine the reactions of the given beam using moment distribution method. w = = 25 kN/m, P₁ = 25 kN, and P₂ = 25 kN RA RB _ || MB Rc _|| = W Numerical answer in 4 decimal places and positive values only: = 8 m 21 B 2m P₁ I 2m P2 2m C kN (Downward) kN-m kN (Upward) kN (Upward)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Please answer the ff in complete solution and draw an fbd use moment distribution method only.
![Determine the reactions of the given beam
using moment distribution method. w =
= 25
kN/m, P₁ = 25 kN, and P₂ = 25 kN
RA
RB
MB
Rc
||
=
W
=
8 m
21
Numerical answer in 4 decimal places and
positive values only:
B 2m
P₁
I
2m
P2
2m C
kN (Downward)
kN-m
kN (Upward)
kN (Upward)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69d8400c-eee6-4c5a-b9f0-27985a5969f1%2Ff0e1f6ad-d7ae-4448-8694-6d061d6d58cf%2F31s2519_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the reactions of the given beam
using moment distribution method. w =
= 25
kN/m, P₁ = 25 kN, and P₂ = 25 kN
RA
RB
MB
Rc
||
=
W
=
8 m
21
Numerical answer in 4 decimal places and
positive values only:
B 2m
P₁
I
2m
P2
2m C
kN (Downward)
kN-m
kN (Upward)
kN (Upward)
![Sign convention-consider clockwise rotation is positive, counterclockwise is negative.
MAR
MBA
Fixed End Moments (FEM) - moment at the wall or fixed joint
MBA
MAB
Stiffness Factor - required moment M to rotate the end A of the beam 0₁ = 1 rad.
4EI
(absolute) K=
far end fixed
3EI
K=far end hinged
M
1
M' = M, far end fixed
(relative) K =, E is constant
L'
3EI
M
(relative) K =
Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment
applied at the other end.
4L
-, far end hinged
B
M' = 0, far end hinged
Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending
stiffness of the member to the sum of bending stiffness of all the members connected to the joint.
к
DF=;
ΣΚ
Note: DF = 1, for hinge or roller support
DF = 0, for fixed support](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69d8400c-eee6-4c5a-b9f0-27985a5969f1%2Ff0e1f6ad-d7ae-4448-8694-6d061d6d58cf%2Fah5xj5l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sign convention-consider clockwise rotation is positive, counterclockwise is negative.
MAR
MBA
Fixed End Moments (FEM) - moment at the wall or fixed joint
MBA
MAB
Stiffness Factor - required moment M to rotate the end A of the beam 0₁ = 1 rad.
4EI
(absolute) K=
far end fixed
3EI
K=far end hinged
M
1
M' = M, far end fixed
(relative) K =, E is constant
L'
3EI
M
(relative) K =
Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment
applied at the other end.
4L
-, far end hinged
B
M' = 0, far end hinged
Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending
stiffness of the member to the sum of bending stiffness of all the members connected to the joint.
к
DF=;
ΣΚ
Note: DF = 1, for hinge or roller support
DF = 0, for fixed support
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