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Determine the reactions of the given beam using moment distribution method. w = = 25 kN/m, P₁ = 25 kN, and P₂ = 25 kN RA RB _ || MB Rc _|| = W Numerical answer in 4 decimal places and positive values only: = 8 m 21 B 2m P₁ I 2m P2 2m C kN (Downward) kN-m kN (Upward) kN (Upward)

Determine the reactions of the given beam using moment distribution method. w = = 25 kN/m, P₁ = 25 kN, and P₂ = 25 kN RA RB _ || MB Rc _|| = W Numerical answer in 4 decimal places and positive values only: = 8 m 21 B 2m P₁ I 2m P2 2m C kN (Downward) kN-m kN (Upward) kN (Upward)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please answer the ff in complete solution and draw an fbd use moment distribution method only.
Determine the reactions of the given beam using moment distribution method. w = = 25 kN/m, P₁ = 25 kN, and P₂ = 25 kN RA RB MB Rc || = W = 8 m 21 Numerical answer in 4 decimal places and positive values only: B 2m P₁ I 2m P2 2m C kN (Downward) kN-m kN (Upward) kN (Upward)
Transcribed Image Text:Determine the reactions of the given beam using moment distribution method. w = = 25 kN/m, P₁ = 25 kN, and P₂ = 25 kN RA RB MB Rc || = W = 8 m 21 Numerical answer in 4 decimal places and positive values only: B 2m P₁ I 2m P2 2m C kN (Downward) kN-m kN (Upward) kN (Upward)
Sign convention-consider clockwise rotation is positive, counterclockwise is negative. MAR MBA Fixed End Moments (FEM) - moment at the wall or fixed joint MBA MAB Stiffness Factor - required moment M to rotate the end A of the beam 0₁ = 1 rad. 4EI (absolute) K= far end fixed 3EI K=far end hinged M 1 M' = M, far end fixed (relative) K =, E is constant L' 3EI M (relative) K = Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment applied at the other end. 4L -, far end hinged B M' = 0, far end hinged Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending stiffness of the member to the sum of bending stiffness of all the members connected to the joint. к DF=; ΣΚ Note: DF = 1, for hinge or roller support DF = 0, for fixed support
Transcribed Image Text:Sign convention-consider clockwise rotation is positive, counterclockwise is negative. MAR MBA Fixed End Moments (FEM) - moment at the wall or fixed joint MBA MAB Stiffness Factor - required moment M to rotate the end A of the beam 0₁ = 1 rad. 4EI (absolute) K= far end fixed 3EI K=far end hinged M 1 M' = M, far end fixed (relative) K =, E is constant L' 3EI M (relative) K = Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment applied at the other end. 4L -, far end hinged B M' = 0, far end hinged Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending stiffness of the member to the sum of bending stiffness of all the members connected to the joint. к DF=; ΣΚ Note: DF = 1, for hinge or roller support DF = 0, for fixed support
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