Determine the reactions at A for the cantilever beam subjected to the distributed and concentrated loads.3.0 kN6.7 kN/m3.7 m1.8 m1.8 mPart 1The free-body diagram of the body is shown. The distributed loading has been replaced with a single equivalent force R at adistance d to the right of point A. Find the magnitude of the force R and the distance d.R3.0 kNdAnswer:R =ikNd =im

Given data: Cantilever beam UVL=6.7 kN/m for span of 3.7m form fixed end point load=3.0 kN for a span of 1.8m from free end In between gap is 1.8m To find Reaction forces at A To Apply Equilibriun equations we need to calculate 'R' for UVL R=12×b×h d=23×length =12×3.7×6.7 R=12.395 kN At a distance d=23×3.7=2.4666m Apply Equilibrium conditions ΣFx=0 ⇒Ax=0 ΣFy=0 R+3kN=Ay 12.395+3=Ay Ay = 15.395 kN ∴Answers Resultant R=12.395 kN distance d=2.466m Reaction forces at A are Ax=0 , Ay =15.395 kN Moment at A ΣMA=0 MA-Ry×2.466-35.5=0 MA=12.395×2.466+3×5.5 MA=47.06 kN-m ∴ MA =47.06 kN-m

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Determine the reactions at A for the cantilever beam subjected to the distributed and concentrated loads. 3.0 kN 6.7 kN/m L- -3.7 m 1.8 m 1.8 m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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