Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pka for HBRO is 8.68. 2. NEXT Based on the given values, set up ICE table in order to determine the unknown. HBRO(aq) H.O(1) H,O (aq) BrO(aq) %3D Initial (M) Change (M) Equilibrium (M) 5 RESET 0.95 0.68 8.68 +x x- +2x 0.95 + 2x 0.95 - 2x 0.68 + x 0.68 - x 0.68 + 2x -2x 0.95 + x 0.95 - x 0.68 - 2x

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I need help with this practice problem regarding acid base and ice tables 

Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pka for HBRO is
8.68.
1
3.
NEXT
Based on the given values, set up ICE table in order to determine the unknown.
HBrO(aq)
H,()
H,O(aq)
BrO(aq)
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
0.95
0.68
8.68
+x
+2x
0.95 - x
0.95 + 2x
0.95 - 2x
0.68 + x
0.68-x
0.68 +2x
-2x
0.95 + x
0.68-2x
Transcribed Image Text:Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pka for HBRO is 8.68. 1 3. NEXT Based on the given values, set up ICE table in order to determine the unknown. HBrO(aq) H,() H,O(aq) BrO(aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 0.95 0.68 8.68 +x +2x 0.95 - x 0.95 + 2x 0.95 - 2x 0.68 + x 0.68-x 0.68 +2x -2x 0.95 + x 0.68-2x
Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pKa for HBRO is
8.68.
PREV
1
3
NEXT
Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not
combine or simplify terms.
Ka
%3D
%D
5 RESET
[x]
[2x]
[2x]?
[0.95 + x]
[0]
[0.95]
[0.68]
[8.68]
[0.68 + x]
[0.68 - x]
[0.68 + 2x]
[0.68 - 2x]
8.68
[0.95 - x]
[0.95 + 2x]
[0.95 - 2x]
0.939
4.79 x 106
2.09 x 109
Transcribed Image Text:Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pKa for HBRO is 8.68. PREV 1 3 NEXT Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka %3D %D 5 RESET [x] [2x] [2x]? [0.95 + x] [0] [0.95] [0.68] [8.68] [0.68 + x] [0.68 - x] [0.68 + 2x] [0.68 - 2x] 8.68 [0.95 - x] [0.95 + 2x] [0.95 - 2x] 0.939 4.79 x 106 2.09 x 109
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