Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 4 ed on your ICE table and Kb expression, determine the pH of the solution. pH %3D

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Determine the pH at the point in the titration of 40.0 mL of 0.200 M H;NNH2 with
0.100 M HNO; after 10.0 mL of the strong acid has been added. The value of Kb
for H2NNH2 is 3.0 x 10-6.
PREV
1
2
3
4
ed on your ICE table and Kb expression, determine the pH of the solution.
pH
5 RESET
4.77 x 10-10
10.8
2.10 x 10-5
4.68
9.32
3.22
0.140
1.70
12.3
Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of 0.200 M H;NNH2 with 0.100 M HNO; after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 ed on your ICE table and Kb expression, determine the pH of the solution. pH 5 RESET 4.77 x 10-10 10.8 2.10 x 10-5 4.68 9.32 3.22 0.140 1.70 12.3
Determine the pH at the point in the titration of 40.0 mL of 0.200 M HNNH2 with
0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb
for H2NNH2 is 3.0 x 10-6.
PREV
1
2
4
NEXT
>
Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine
the unknown. Do not combine or simplify terms.
= 3.0 x 10-6
RESET
[0]
[0.200]
[0.0200]
[0.100]
[0.140]
[0.175]
[x]
[2x]
[0.200 + x]
[0.200 - x]
[0.0200 + x]
[0.0200 - x]
[0.100 + x]
[0.100 - x]
[0.140 + x]
[0.140 - x]
[0.175 + x]
[0.175 - x]
Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of 0.200 M HNNH2 with 0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 4 NEXT > Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do not combine or simplify terms. = 3.0 x 10-6 RESET [0] [0.200] [0.0200] [0.100] [0.140] [0.175] [x] [2x] [0.200 + x] [0.200 - x] [0.0200 + x] [0.0200 - x] [0.100 + x] [0.100 - x] [0.140 + x] [0.140 - x] [0.175 + x] [0.175 - x]
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