Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. 2 NEXT Use the table below to determine the moles of reactant and product after the reaction of the acid and base. H:NNH:(aq) H(aq) H:NNH3*(aq) + Before (mol) Change (mol) After (mol)
Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. 2 NEXT Use the table below to determine the moles of reactant and product after the reaction of the acid and base. H:NNH:(aq) H(aq) H:NNH3*(aq) + Before (mol) Change (mol) After (mol)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with
0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb
for H2NNH2 is 3.0 x 10-6.
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2
3
4
NEXT
>
Use the table below to determine the moles of reactant and product after the reaction of the acid
and base.
H2NNH2(aq)
H*(aq)
H2NNH:*(aq)
+
Before (mol)
Change (mol)
After (mol)
RESET
0.200
0.100
1.00 x 10-3
-1.00 x 103
2.00 x 10-3
-2.00 x 10-3
6.00 x 10-3
-6.00 x 10-3
7.00 x 10-3
-7.00 x 10-3
8.00 x 10-3
-8.00 x 10-3
Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with
0.100 M HNO: after 10.0 mL of the strong acid has been added. The value of Kb
for H2NNH2 is 3.0 x 10-6.
PREV
1
2
3
4
NEXT
Based on the result of the acid-base reaction, set up the ICE table in order to determine the
unknown.
H:NNH:(aq)
H:O(I)
OH (aq)
H2NNH3*(aq)
+
Initial (M)
Change (M)
Equilibrium (M)
RESET
0.200
0.0200
0.100
0.140
0.175
+x
0.200 + x
0.200 - x
0.0200 + x
0.0200 - x
0.100 + x
0.100- х
0.140 + x
-X
0.140 - x
0.175 + x
0.175 - x
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