Determine the pH at the equivalence point in the titration of 50.0 mL of 0.300 M CH;COOH with 0.300 M NaOH. The value of Ka for CH3COOH is 1.8 x 10-5.

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Question 12 of 18
Determine the pH at the equivalence point in the titration of 50.0 mL of 0.300 M
CH;COOH with 0.300 M NaOH. The value of Ka for CH3COOH is 1.8 × 10-5.
1
2
3
4
NEXT
Use the table below to determine the moles of reactant and product after the reaction of the acid
and base. You can ignore the amount of liquid water in the reaction.
CH;COOH(aq) +
ОН (ад)
H2O(1)
+ CH3COO (aq)
Before (mol)
Change (mol)
After (mol)
5 RESET
0.300
-0.300
+x+
0.300 + x
0.300 - x
15.0
-15.0
0.0300
-0.0300
0.150
-0.150
0.0150
-0.0150
50.0
-50.0
Transcribed Image Text:.10Tedu.CO Question 12 of 18 Determine the pH at the equivalence point in the titration of 50.0 mL of 0.300 M CH;COOH with 0.300 M NaOH. The value of Ka for CH3COOH is 1.8 × 10-5. 1 2 3 4 NEXT Use the table below to determine the moles of reactant and product after the reaction of the acid and base. You can ignore the amount of liquid water in the reaction. CH;COOH(aq) + ОН (ад) H2O(1) + CH3COO (aq) Before (mol) Change (mol) After (mol) 5 RESET 0.300 -0.300 +x+ 0.300 + x 0.300 - x 15.0 -15.0 0.0300 -0.0300 0.150 -0.150 0.0150 -0.0150 50.0 -50.0
Question 12 of 18
Determine the pH at the equivalence point in the titration of 50.0 mL of 0.300 M
CH3COOH with 0.300 M NaOH. The value of Ka for CH3COOH is 1.8 x 10-5.
3
4
NEXT
PREV
Based on the result of the acid-base reaction, set up the ICE table in order to determine the
unknown.
CH;COO"(aq) +
H;O(1)
ОН (ад)
+ CH;COOH(aq)
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
0.300
0.0300
0.150
0.0150
0.0200
+x
1111
0.300 + x
0.300 - x
0.0300 + x
0.0300 - x
0.150 + x
0.150 - x
0.0150 + x
-X
0.0150 - x
0.0200 + x
0.0200 - x
Transcribed Image Text:Question 12 of 18 Determine the pH at the equivalence point in the titration of 50.0 mL of 0.300 M CH3COOH with 0.300 M NaOH. The value of Ka for CH3COOH is 1.8 x 10-5. 3 4 NEXT PREV Based on the result of the acid-base reaction, set up the ICE table in order to determine the unknown. CH;COO"(aq) + H;O(1) ОН (ад) + CH;COOH(aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 0.300 0.0300 0.150 0.0150 0.0200 +x 1111 0.300 + x 0.300 - x 0.0300 + x 0.0300 - x 0.150 + x 0.150 - x 0.0150 + x -X 0.0150 - x 0.0200 + x 0.0200 - x
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