Determine the output of the following code: char f[10] = "alpha-5"; char g[11] = "0123456789"; size_t j = 0; for (size_t i=0; i < strlen(f); i++){ %3D %3D if (isalpha(f[i])) g[j++] = f[i]; cout << g << endl;
Determine the output of the following code: char f[10] = "alpha-5"; char g[11] = "0123456789"; size_t j = 0; for (size_t i=0; i < strlen(f); i++){ %3D %3D if (isalpha(f[i])) g[j++] = f[i]; cout << g << endl;
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
![**Determine the output of the following code:**
```cpp
char f[10] = "alpha-5";
char g[11] = "0123456789";
size_t j = 0;
for (size_t i = 0; i < strlen(f); i++) {
if (isalpha(f[i])) {
g[j++] = f[i];
}
}
cout << g << endl;
```
**Options:**
- alpha
- Unknown output
- alpha56789
- It will not compile
**Explanation:**
This C++ code snippet is designed to filter and copy only the alphabetic characters from the array `f` to the array `g`. The loop iterates over each character in the string `f` and uses the `isalpha()` function to check if the character is alphabetic. If it is, the character is copied to the `g` array at the current position of `j`, which is then incremented.
Given the initialization of `f` as "alpha-5", the alphabetic characters "alpha" are extracted, and `g` becomes "alpha56789".
Therefore, the output of this code, when printed, will be `alpha`.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1ff8e04-1415-4538-97d2-6a2f07e52bad%2Fe2ef29c6-d8a1-40e2-b5c7-20b2a377e986%2Fiqqvzpi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Determine the output of the following code:**
```cpp
char f[10] = "alpha-5";
char g[11] = "0123456789";
size_t j = 0;
for (size_t i = 0; i < strlen(f); i++) {
if (isalpha(f[i])) {
g[j++] = f[i];
}
}
cout << g << endl;
```
**Options:**
- alpha
- Unknown output
- alpha56789
- It will not compile
**Explanation:**
This C++ code snippet is designed to filter and copy only the alphabetic characters from the array `f` to the array `g`. The loop iterates over each character in the string `f` and uses the `isalpha()` function to check if the character is alphabetic. If it is, the character is copied to the `g` array at the current position of `j`, which is then incremented.
Given the initialization of `f` as "alpha-5", the alphabetic characters "alpha" are extracted, and `g` becomes "alpha56789".
Therefore, the output of this code, when printed, will be `alpha`.
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