Determine the number of valence electrons in NH2OH and then draw the corresponding Lewis structure. A) 16 B) 14 C) 13 D) 10 E) 15 Click to edit molecule
Formal Charges
Formal charges have an important role in organic chemistry since this concept helps us to know whether an atom in a molecule is neutral/bears a positive or negative charge. Even if some molecules are neutral, the atoms within that molecule need not be neutral atoms.
Polarity Of Water
In simple chemical terms, polarity refers to the separation of charges in a chemical species leading into formation of two polar ends which are positively charged end and negatively charged end. Polarity in any molecule occurs due to the differences in the electronegativities of the bonded atoms. Water, as we all know has two hydrogen atoms bonded to an oxygen atom. As oxygen is more electronegative than hydrogen thus, there exists polarity in the bonds which is why water is known as a polar solvent.
Valence Bond Theory Vbt
Valence bond theory (VBT) in simple terms explains how individual atomic orbitals with an unpaired electron each, come close to each other and overlap to form a molecular orbital giving a covalent bond. It gives a quantum mechanical approach to the formation of covalent bonds with the help of wavefunctions using attractive and repulsive energies when two atoms are brought from infinity to their internuclear distance.
![**Question:**
Determine the number of valence electrons in NH₂OH and then draw the corresponding Lewis structure.
**Options:**
- A) 16
- B) 14
- C) 13
- D) 10
- E) 15
**Correct Answer:**
- B) 14
**Explanation:**
This problem asks you to find the number of valence electrons in NH₂OH and draw its Lewis structure.
**Diagram Analysis:**
On the right is a simplified Lewis structure diagram, showing a basic representation of a molecule with two atoms connected by a single bond. This is not a complete drawing for NH₂OH but demonstrates the concept of a bond between two atoms.
In constructing the full Lewis structure of NH₂OH:
1. **Nitrogen (N)** has 5 valence electrons.
2. **Each Hydrogen (H)** has 1 valence electron, contributing 3 valence electrons in total.
3. **Oxygen (O)** has 6 valence electrons.
Adding these together gives:
\[ 5 (\text{N}) + 3 (\text{H's}) + 6 (\text{O}) = 14 \text{ valence electrons}. \]
The task involves placing pairs of electrons to satisfy the octet rule, starting with single bonds between N, O, and H, with lone pairs remaining on N and O. This will be the correct arrangement with a total of 14 valence electrons.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff0c1ca81-963e-4668-a5af-b3c412b423c8%2F00f77485-91ec-4b8c-a108-c9fc97371486%2F5wxuf7_processed.png&w=3840&q=75)
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