Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. 1) LIAIH4 (1 equiv) 2) H30* O: Blank # 1 Blank # 2
Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. 1) LIAIH4 (1 equiv) 2) H30* O: Blank # 1 Blank # 2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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One product is ethanol but the other is not propanol or 1-propanol and I cant figure out what it is
Reaction Conditions:
1. LiAlH<sub>4</sub> (Lithium aluminum hydride, 1 equivalent)
2. H<sub>3</sub>O<sup>+</sup> (Hydronium ion)
**Blanks for answers:**
- Blank #1: [input field]
- Blank #2: [input field]
### Explanation of the Reaction Diagram
In the given diagram:
- The reactant contains an ester functional group with the structure CH<sub>3</sub>-COO-CH<sub>2</sub>-R, where 'R' represents the alkyl group attached to the oxygen atom.
- The ester is subjected to reduction using Lithium aluminum hydride (LiAlH<sub>4</sub>), followed by an acidic workup with hydronium ions (H<sub>3</sub>O<sup>+</sup>).
### Step-by-Step Reaction Mechanism
1. **LiAlH<sub>4</sub> Reduction:**
- Lithium aluminum hydride is a strong reducing agent that converts esters into two primary alcohols.
- The ester’s carbonyl carbon (C=O) gets reduced, breaking the C-O bond and adding hydrogen atoms.
2. **Hydronium Ion Workup:**
- The hydronium ion workup step is used to protonate any anionic intermediate, resulting in the formation of neutral alcohol molecules.
### Expected Products:
For the given ester:
- The ester gets reduced to form a primary alcohol corresponding to the acyl part (C=O) and the alkyl part (R).
### Based on the Provided Diagram:
- The specific ester in the diagram is **Ethyl Acetate (CH<sub>3</sub>-COO-CH<sub>2</sub>CH<sub>3</sub>).
### Reduction Products:
- **Ethanol (CH<sub>3</sub>-CH<sub>2</sub>-OH)**
- **Methanol (CH<sub>3</sub>-OH)**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6c48281-bcf8-4d84-ad3c-d8fb9e0661f0%2F1826435a-c219-4aad-9ad5-2a9a325666a9%2Fope0r3_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding LiAlH<sub>4</sub> Reduction Reactions
**Problem Statement:**
Determine the name of the product(s) for the following reaction (disregard stereochemistry). If there is no reaction, then submit the name of the reactant.
**Chemical Reaction:**
Reaction Conditions:
1. LiAlH<sub>4</sub> (Lithium aluminum hydride, 1 equivalent)
2. H<sub>3</sub>O<sup>+</sup> (Hydronium ion)
**Blanks for answers:**
- Blank #1: [input field]
- Blank #2: [input field]
### Explanation of the Reaction Diagram
In the given diagram:
- The reactant contains an ester functional group with the structure CH<sub>3</sub>-COO-CH<sub>2</sub>-R, where 'R' represents the alkyl group attached to the oxygen atom.
- The ester is subjected to reduction using Lithium aluminum hydride (LiAlH<sub>4</sub>), followed by an acidic workup with hydronium ions (H<sub>3</sub>O<sup>+</sup>).
### Step-by-Step Reaction Mechanism
1. **LiAlH<sub>4</sub> Reduction:**
- Lithium aluminum hydride is a strong reducing agent that converts esters into two primary alcohols.
- The ester’s carbonyl carbon (C=O) gets reduced, breaking the C-O bond and adding hydrogen atoms.
2. **Hydronium Ion Workup:**
- The hydronium ion workup step is used to protonate any anionic intermediate, resulting in the formation of neutral alcohol molecules.
### Expected Products:
For the given ester:
- The ester gets reduced to form a primary alcohol corresponding to the acyl part (C=O) and the alkyl part (R).
### Based on the Provided Diagram:
- The specific ester in the diagram is **Ethyl Acetate (CH<sub>3</sub>-COO-CH<sub>2</sub>CH<sub>3</sub>).
### Reduction Products:
- **Ethanol (CH<sub>3</sub>-CH<sub>2</sub>-OH)**
- **Methanol (CH<sub>3</sub>-OH)**
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