Determine the most economical size of a 3-phase line which supplies the following loads at 10 kV : (1) 100 kW at 0-8 p.f. (lag) for 10 hours (ii) 500 kW at 0-9 p.f. (lag) for 8 hours (ii) 100 kW at unity p.f. for 6 hours. The above gives the daily load cycle. The cost per km of the completely erected line is Rs (8000 a 1500) where a is the area of cross-section of each conductor. The combined interest and depreciation per annum of capital cost. Cost of energy losses is 5 paise per kWh. Resistivity of conducto 10%

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Determine the most economical size of a 3-phase line which supplies the following loads at 10 kV :
(1) 100 kW at 0-8 p.f. (lag) for 10 hours
(ii) 500 kW at 0-9 p.f. (lag) for 8 hours
(ii) 100 kW at unity p.f. for 6 hours.
The above gives the daily load cycle. The cost per km of the completely erected line is Rs (8000 a +
1500) where a is the area of cross-section of each conductor. The combined interest and depreciation is
10% per annum of capital cost. Cost of energy losses is 5 paise per kWh. Resistivity of conductor
material = 1-72× 10"Q cm.
|0 844 em'|
%3D
Transcribed Image Text:Determine the most economical size of a 3-phase line which supplies the following loads at 10 kV : (1) 100 kW at 0-8 p.f. (lag) for 10 hours (ii) 500 kW at 0-9 p.f. (lag) for 8 hours (ii) 100 kW at unity p.f. for 6 hours. The above gives the daily load cycle. The cost per km of the completely erected line is Rs (8000 a + 1500) where a is the area of cross-section of each conductor. The combined interest and depreciation is 10% per annum of capital cost. Cost of energy losses is 5 paise per kWh. Resistivity of conductor material = 1-72× 10"Q cm. |0 844 em'| %3D
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