Determine the molecular formula of a compound with an empirical formula of NH2 and a formula mass of 32.06 amu. The empirical formula of a hydrocarbon (compound that contains only C and H) is found to be CH. Laboratory procedures have found that the molar mass of the compound is 78 g/mol. What is the molecular formula of this compound?

Q: A particular carborane has the following mass percentages: 26.35%C and 59.28%B. What is the…

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Q: molecular formula

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Q: A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is…

A: Given,Percent of B in the compound = 40.28 %Percent of N in the compound = 52.20 %Percent of H in…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A: Solution Given data, The amount of CO2 = 33.01g The amount of H2O = 13.52g Number of moles of…

Q: An organic compound consists of Carbon, hydrogen and sulfur. Complete combustion of 3.50 g this…

A: The given compound consist of carbon, hydrogen and sulfur. We have to determine the empirical…

Q: A 2.41 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given, mass of 2.41 g sample of a compound produced 1.36 g CO2 and 0.833 g H2O. Moles of…

Q: Determine the empirical formula of a compound having the following elemental analysis: 52.2% C;…

A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: An Organic compound contains 59.00% by mass C, 7.15% by mass H, 7.65% by mass N, and 26.20% by mass…

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Q: a) Determine molecules of C5H5N in 16.00 g of C5H5N (molar mass = 79.11g/mol). b) Explain how the…

A: a) Given : Mass of C5H5N = 16.00 g And molar mass of C5H5N = 79.11 g/mol.

Q: When 2.115 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.637 grams…

A: First of all we calculate the mass of Carbon in Carbon dioxide and mass of Hydrogen in water. Then…

Q: Consider the following reaction of K2S2O3 for neutralizing chlorine in industrial bleaching. K2S2O3…

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Q: II. Empirical Formula 1. A compound contains 40.92 % C, 4.58% H, and 54.50% O by mass. What is the…

A: Determination of empirical formula The percentage composition of elements present in given compound…

Q: When 3.433 grams of a hydrocarbon, C,Hy, were burnec in a combustion analysis apparatus, 10.52 grams…

A: Mass of Hydrocarbon = 3.433 grams Molar mass of Hydrocarbon = 86.18 grams Number of moles of…

Q: An unknown compound contains only CC , HH , and OO . Combustion of 9.00 g9.00 g of this compound…

A: The mass of the organic compound is = 9.00 g The mass of carbon dioxide formed is = 20.5 g The molar…

Q: A 2.86 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given, mass of 2.86 g sample of a compound produced 1.61 g CO2 and 0.989 g H2O.Moles of CO2 and H2O…

Q: A 3.260 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

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Q: 3.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have…

A: Given that,Mass of compound, which is made up of carbon, hydrogen and oxygen = Molecular mass of…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. Calculate the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: You are working in a science lab that is analyzing the contents of cow manure. You discover a novel…

A: Empirical formula is the simplest formula of the compound, which is the ratio of subscripts of the…

Q: Determine the molecular formula of the compound with an empirical formula of CH and a molar mass of…

A: Given:- Determine the molecular formula of the compound with an empirical formula of CH and a molar…

Q: Combustion analysis of a compound yields: C 78.52%, H 8.39%, N 8.33%, and O 4.76%. Determine the…

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Q: A strikingly beautiful copper compound with the common name “blue vitriol” has the following…

A: Since the compound is having Cu, S, H and O hence we can say that the empirical formula of compound…

Q: Part D. A 28.50 g sample of a compound of carbon, sulfur, hydrogen, and combusted (burned). 35.25 g…

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Q: An unknown compound contains only C , H , and O . Combustion of 6.90 g of this compound produced…

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Q: Determine molecular formula. An organic compound that only contains C, H, and O was subjected to…

A: Since the compound is made up of only C, H and O. Hence we can assume the empirical formula of…

Q: A 2.260 gram sample of an organic compound containing C,H, and O is analyzed by combustion analysis…

A: Empirical formula represents the simplest whole number ratio of atoms of elements present in the…

Q: a compound contains only hydrogen, carbon, and oxygen. combustion of 10.68mg of the compound…

A: The combustion reaction of given compound and its masses are shown below,

Q: A 27.129 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put…

A: Answer: Empirical formula is the formula containing all the atoms present in the compound in their…

Q: Complete combustion of 3.40 g3.40 g of a hydrocarbon produced 10.9 g10.9 g of CO2CO2 and 3.89 g3.89…

A: Empirical formula :-  The formula which shows only relative number (simple ratio) of atoms of…

Q: An unknown compound contains only C , H , and O . Combustion of 5.00 g of this compound produced…

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Q: A 3.76 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given: mass of sample = 3.76 g mass of CO2 = 2.12 g mass of H2O = 1.30 g 5.92 g produced 6.07 g SO3…

Q: A compound is 7.7% (by mass) hydrogen and 92.7 % carbon. It has a molecular weight of 52 g/mole.…

A: Empirical formula are the formula which represent simplest ratio of an element present in a given…

Q: 3. Hydrated vanadium (II) sulfate, VSO4-XH2O, is 46.19% water by mass. Determine the empirical…

A: Given  mass percent of water in hydrated salt = 46.19% Atomic mass of V = 50.94 amu Atomic mass of S…

Q: 1.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have…

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Q: 2.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have…

A: Empirical formula :- The formula which gives the simplest whole number ratio of atoms of various…

Q: A 2.664 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: Consider the given information is as follows;Mass of the organic compound sample = 2.664 gMass of  =…

Q: 1.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have…

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Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

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Q: The complete combustion of 4.10 g of a hydrocarbon produced 12.4 g of CO, and 6.35 g of H, 0. What…

A: We have hydrocarbon meaning only C and H so we don't have to care of O. Carbon involved in…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.