Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 0.80 ounce. (b) The sample mean is 127 ounces. With a sample size of 13, a 90% level of confidence, and a population standard deviation of 0.80 ounce, does it seem possible that the population mean could be exactly 128 ounces? Explain.
Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 0.80 ounce. (b) The sample mean is 127 ounces. With a sample size of 13, a 90% level of confidence, and a population standard deviation of 0.80 ounce, does it seem possible that the population mean could be exactly 128 ounces? Explain.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
A paint manufacturer uses a machine to fill gallon cans with paint (1
mean volume of paint the machine is putting in the cans within
normally distributed.
gal=128
ounces). The manufacturer wants to estimate the 0.4
ounce. Assume the population of volumes is (a) Determine the minimum sample size required to construct a
90%
confidence interval for the population mean. Assume the population standard deviation is
0.80
ounce.(b) The sample mean is
127
ounces. With a sample size of
13,
a
90%
level of confidence, and a population standard deviation of
0.80
ounce, does it seem possible that the population mean could be exactly
128
ounces? Explain.Click here to view page 1 of the Standard Normal Table.
Click here to view page 2 of the Standard Normal Table.
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(a) The minimum sample size required to construct a
90%
confidence interval is
nothing
cans.(Round up to the nearest whole number.)
Expert Solution
Step 1
(a)
Given :
Margin of error=E=0.4
Population standard deviation=σ=0.80
Significance level=α=0.10
The critical value is , Zα/2=Z0.10/2=1.645 ; The Excel function is , =NORMSINV(0.10/2)
Our aim is to find the sample size.
(b)
Given : n=13 , X-bar=127 , σ=0.80 , α=0.10
Our aim is to find the 90% confidence interval.
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