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Determine the mass of citric acid per 240 mL of the vegtable juice.

Determine the mass of citric acid per 240 mL of the vegtable juice.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4. Determine the mass of citric acid per 240 mL of the vegtable juice. 

**Titration Analysis of Vegetable Juice** The following questions pertain to a titration experiment analyzing citric acid in a vegetable juice sample. **Experimental Data:** - A 24.8 mL sample of vegetable juice is titrated with 15.65 mL of NaOH solution. - The molar concentration of the NaOH solution is 0.106 M. - The molar mass of citric acid is 192.12 g/mol. **Instructions:** - All answers should be expressed with 3 significant figures using appropriate units. ### Questions: **2. Determine the molar concentration of citric acid in the vegetable juice sample.** - Calculation: - Moles of NaOH used = 15.65 mL × 0.106 M = 1.6589 mmol - Moles of citric acid = 1.6589 mmol (since it's a 1:1 titration) - Molar concentration = 1.6589 mmol / 24.8 mL = 0.0665444 M - Answer: 0.0665 M **3. Determine the number of moles of citric acid per 240 mL of the vegetable juice.** - Use the molar concentration from Question 2 to calculate the moles in 240 mL. **4. Determine the mass of citric acid per 240 mL of the vegetable juice.** - Use the molar mass of citric acid to convert moles from Question 3 to grams. **5. If the label on the bottle lists the citric acid content as 1 g per serving with a serving size of 240 mL, determine the percent error in the titration results. Express result with 2 significant figures.** - Calculate the percent error based on the difference between the experimental and label values. - Formula: Percent Error = [(Experimental Value - Label Value) / Label Value] × 100% This setup provides a comprehensive guide for students to engage with real-world chemical analysis applications.
Transcribed Image Text:**Titration Analysis of Vegetable Juice** The following questions pertain to a titration experiment analyzing citric acid in a vegetable juice sample. **Experimental Data:** - A 24.8 mL sample of vegetable juice is titrated with 15.65 mL of NaOH solution. - The molar concentration of the NaOH solution is 0.106 M. - The molar mass of citric acid is 192.12 g/mol. **Instructions:** - All answers should be expressed with 3 significant figures using appropriate units. ### Questions: **2. Determine the molar concentration of citric acid in the vegetable juice sample.** - Calculation: - Moles of NaOH used = 15.65 mL × 0.106 M = 1.6589 mmol - Moles of citric acid = 1.6589 mmol (since it's a 1:1 titration) - Molar concentration = 1.6589 mmol / 24.8 mL = 0.0665444 M - Answer: 0.0665 M **3. Determine the number of moles of citric acid per 240 mL of the vegetable juice.** - Use the molar concentration from Question 2 to calculate the moles in 240 mL. **4. Determine the mass of citric acid per 240 mL of the vegetable juice.** - Use the molar mass of citric acid to convert moles from Question 3 to grams. **5. If the label on the bottle lists the citric acid content as 1 g per serving with a serving size of 240 mL, determine the percent error in the titration results. Express result with 2 significant figures.** - Calculate the percent error based on the difference between the experimental and label values. - Formula: Percent Error = [(Experimental Value - Label Value) / Label Value] × 100% This setup provides a comprehensive guide for students to engage with real-world chemical analysis applications.
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