Determine the magnitude resulting from the intensity of the electric field at point P directed by two point charges q1 = 7μC and q2 = -2μC
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Good morning, could you help me solve the following problem in a vectorial way?
Thanks in advance.
Determine the magnitude resulting from the intensity of the electric field at point P directed by two point charges q1 = 7μC and q2 = -2μC Distributed as follows: Observe the image.
what would the free body diagram look like?
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- Consider an infinitely long cylinder with radius R. The cylinder is an insulator and it is positively charged, the charge per unit of length is A. (Hint: because it is an insulator you should assume that the charge is spread uniformly across its entire volume). By reflecting on the symmetry of the charge distribution of the system, determine what a) the E-field lines look like around the cylinder. Describe the E-field in words and with a simple sketch. In order to give a complete description of the E-field lines make two sketches: i) one with a side view of the cylinder, ii) one with a cross-sectional view of the cylinder. Make sure to also show the direction of the E-field lines. b) (-- . the figure. Your goal for this part is to properly use Gauss' law to calculate the electric field at point P. Follow the 5 steps below. Consider a point P outside the cylinder, at a distance d from its axis, d > R, as shown inAnswer all parts (a,b,c) of the physics problem. thanks!Please show all the steps, and solution separate at the end. Part (a) Do this for the range r > R. Part (b) Do this for the range r < R.
- Part B What is the maximum mass mmax that would prevent the particle from falling indefinitely? Express your answer in terms of some or all of the variables q, o, R, the acceleration due to gravity g, and the electric constant €0. mmax = Submit ΑΣΦ Request Answer Consider an infinite flat sheet with positive charge density in which a circular hole of radius R has been cut out. The sheet lies in the zy-plane with the origin at the center of the hole. The sheet is parallel to the ground, so that the positive z-axis describes the "upward" direction. If a particle of mass m and negative charge - sits at rest at the center of the hole and is released, the particle, constrained to the z-axis, begins to fall. As it drops farther beneath the sheet, the upward electric force increases. For a sufficiently low value of m, the upward electrical attraction eventually exceeds the particle's weight and the particle will slow, come to a stop, and then rise back to its original position. This sequence…Problem 2 Consider the Gaussian surface shown in Figure 2. A uniform external electric field E, having magnitude 3.20 x 103 N/C and parallel to the xz plane with an angle of 36.87° measured from the +x axis toward the +z axis, enters through face 1 (back face). In addition, a uniform electric field E, of magnitude 6.40 x 103 N/C traveling in the same direction as E, , flows outwardly through face 2 (front face). 0,45 m 0,30 m En 0.50 m Figure 2. Gaussian surface in the form of a prism through which two fields pass.