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Determine the local maximum and minimum values of f(x)=2x³+3x²-12x+4 using the second derivative test when it applies. Local maximum value is 17 at x = - 1. Local minimum value is 8 at x = 2. Local maximum value is 24 at x = -2. Local minimum value is -3 at x = 1. Local minimum value is 24 at x = -2. Local maximum value is -3 at x = 1. Local minimum value is 17 at x = -1. Local maximum value is 8 at x = 2.

Determine the local maximum and minimum values of f(x)=2x³+3x²-12x+4 using the second derivative test when it applies. Local maximum value is 17 at x = - 1. Local minimum value is 8 at x = 2. Local maximum value is 24 at x = -2. Local minimum value is -3 at x = 1. Local minimum value is 24 at x = -2. Local maximum value is -3 at x = 1. Local minimum value is 17 at x = -1. Local maximum value is 8 at x = 2.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine the local maximum and minimum values of f(x)=2x³+3x²-12x+4 using the second derivative test when it applies. Local maximum value is 17 at x = - 1. Local minimum value is 8 at x = 2. Local maximum value is 24 at x = -2. Local minimum value is -3 at x = 1. Local minimum value is 24 at x = -2. Local maximum value is -3 at x = 1. Local minimum value is 17 at x = -1. Local maximum value is 8 at x = 2.
Transcribed Image Text:Determine the local maximum and minimum values of f(x)=2x³+3x²-12x+4 using the second derivative test when it applies. Local maximum value is 17 at x = - 1. Local minimum value is 8 at x = 2. Local maximum value is 24 at x = -2. Local minimum value is -3 at x = 1. Local minimum value is 24 at x = -2. Local maximum value is -3 at x = 1. Local minimum value is 17 at x = -1. Local maximum value is 8 at x = 2.
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