How can I answer this one as well?? **Part H: Calculating the Mass of H₂O Produced**You are given the task to calculate the grams of H₂O (water) that would be produced in a chemical reaction. Ensure that your answer is expressed with the appropriate units.**Input Section:**- You will find a text box labeled "m(H₂O) =" where you need to enter: - **Value:** The numerical result of your calculation. - **Units:** The units of measurement for your answer (e.g., grams).**Interactive Tools:**- The interface provides tools for entering mathematical symbols and units. These include options for scientific notation, Greek letters, and unit symbols.**Options:**- **Submit:** Click here when ready to submit your answer.- **Request Answer:** Use this if you need guidance or assistance.**Feedback and Navigation:**- **Provide Feedback:** Option available for submitting feedback on the problem.- **Next:** Button to navigate to the subsequent part of the activity.**Branding:**- The bottom of the page is branded with "Pearson," indicating the educational provider of this content.This exercise helps reinforce skills in stoichiometry and unit conversion, which are crucial in chemistry. **Limiting Reactant Determination**To determine the limiting reactant, given 31.0 g of each reactant in the following chemical reaction:\[ \text{C}_2\text{H}_6\text{O(l)} + 3\text{O}_2(g) \rightarrow 2\text{CO}_2(g) + 3\text{H}_2\text{O(g)} \]### Possible Reactants:- \(\text{H}_2\text{O}\)- \(\text{C}_2\text{H}_6\text{O}\)- \(\text{O}_2\)- \(\text{CO}_2\)### Solution:**Step-by-Step Calculation:**1. **Moles of CO\(_2\) from C\(_2\)H\(_6\)O:** \[ \text{moles of CO}_2 = 31.0 \, \text{g} \, \text{C}_2\text{H}_6\text{O} \times \frac{1 \, \text{mol} \, \text{C}_2\text{H}_6\text{O}}{46.07 \, \text{g}} \times \frac{2 \, \text{mol} \, \text{CO}_2}{1 \, \text{mol} \, \text{C}_2\text{H}_6\text{O}} = 1.35 \, \text{mol CO}_2 \]2. **Moles of CO\(_2\) from O\(_2\):** \[ \text{moles of CO}_2 = 31.0 \, \text{g} \, \text{O}_2 \times \frac{1 \, \text{mol} \, \text{O}_2}{32.00 \, \text{g}} \times \frac{2 \, \text{mol} \, \text{CO}_2}{3 \, \text{mol} \, \text{O}_2} = 0.646 \, \text{mol CO}_2 \]### Conclusion:Since the number of moles produced by O\(_2\)

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Answered: Determine the limiting reactant, given…

Science

Chemistry

Determine the limiting reactant, given 31.0 g of each reactant, in the following: C,H6O(1) + 302 (g) 2CO2 (g) + 3H2O(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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