Determine the limit at infinity. 7x32x²+3x X-00 -x³-2x+7 9) lim

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Determine the limit at infinity.**

\[ \lim_{{x \to -\infty}} \frac{7x^3 - 2x^2 + 3x}{-x^3 - 2x + 7} \]

In this problem, we need to evaluate the limit of a rational function as \( x \) approaches negative infinity. The expression is a fraction where the numerator is \( 7x^3 - 2x^2 + 3x \) and the denominator is \(-x^3 - 2x + 7\).

Approaching the limit, we focus on the terms with the highest degree of \( x \) in both the numerator and the denominator to simplify the process. Here, the highest power of \( x \) in both the numerator and denominator is \( x^3 \).

Therefore, the limit simplifies to:

\[ \lim_{{x \to -\infty}} \frac{7x^3}{-x^3} = \lim_{{x \to -\infty}} -7 = -7. \]

Thus, the limit is \(-7\).

**Explanation of Process:**

1. Identify the highest degree term of \( x \) in both the numerator and the denominator.
2. Divide both the numerator and denominator by \( x^3 \).
3. Simplify the expression as \( x \) approaches negative infinity.
4. The resulting limit is determined by the leading coefficients of these terms, which leads to the value of \(-7\).
Transcribed Image Text:**Determine the limit at infinity.** \[ \lim_{{x \to -\infty}} \frac{7x^3 - 2x^2 + 3x}{-x^3 - 2x + 7} \] In this problem, we need to evaluate the limit of a rational function as \( x \) approaches negative infinity. The expression is a fraction where the numerator is \( 7x^3 - 2x^2 + 3x \) and the denominator is \(-x^3 - 2x + 7\). Approaching the limit, we focus on the terms with the highest degree of \( x \) in both the numerator and the denominator to simplify the process. Here, the highest power of \( x \) in both the numerator and denominator is \( x^3 \). Therefore, the limit simplifies to: \[ \lim_{{x \to -\infty}} \frac{7x^3}{-x^3} = \lim_{{x \to -\infty}} -7 = -7. \] Thus, the limit is \(-7\). **Explanation of Process:** 1. Identify the highest degree term of \( x \) in both the numerator and the denominator. 2. Divide both the numerator and denominator by \( x^3 \). 3. Simplify the expression as \( x \) approaches negative infinity. 4. The resulting limit is determined by the leading coefficients of these terms, which leads to the value of \(-7\).
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