Determine the largest interval (a,b) for which the existence of a unique solution using Theorem 1 in section 6.1, guarantees the existence of a unique solution on (a,b) to the given initial values Y(-) = 1. y(→) = y"() = o x(x + 1)y"' – 3xy' + y = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 27E
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Existence and Uniqueness
Theorem 1. Suppose p1 (x), ..., P,(x) and g(x) are each continuous on an
interval (a, b) that contains the point xo. Then, for any choice of the initial values
Yo, Y1, · . . , Yn-1, there exists a unique solution y(x) on the whole interval (a, b) to the
initial value problem
y(") (x) + P1(x)y("-1)(x) + •… +
+ Pn (x )y(x) = g(x),
(3)
(п —
(4)
y (xo) = Yo, y' (xo) = Y1, . . , y"-1) (xo) = Yn-1:
= Yn - 1•
Transcribed Image Text:Existence and Uniqueness Theorem 1. Suppose p1 (x), ..., P,(x) and g(x) are each continuous on an interval (a, b) that contains the point xo. Then, for any choice of the initial values Yo, Y1, · . . , Yn-1, there exists a unique solution y(x) on the whole interval (a, b) to the initial value problem y(") (x) + P1(x)y("-1)(x) + •… + + Pn (x )y(x) = g(x), (3) (п — (4) y (xo) = Yo, y' (xo) = Y1, . . , y"-1) (xo) = Yn-1: = Yn - 1•
Determine the largest interval (a,b) for which the
existence of a unique solution using Theorem 1 in section
6.1, guarantees the existence of a unique solution on (a,b)
to the given initial values
>(-)=1.
= 1, y() = y"(-) = o
x(х + 1)у" — Зху' + у %3D0
Transcribed Image Text:Determine the largest interval (a,b) for which the existence of a unique solution using Theorem 1 in section 6.1, guarantees the existence of a unique solution on (a,b) to the given initial values >(-)=1. = 1, y() = y"(-) = o x(х + 1)у" — Зху' + у %3D0
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