determine the intervals in which the following functions are increasing, decreasing, concave up and concave down f(x)=8x1/3+x4/3

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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determine the intervals in which the following functions are increasing, decreasing, concave up and concave down

f(x)=8x1/3+x4/3

Expert Solution
Step 1

The given function f(x) is,

f(x)=8x13+x43

Critical point is the point at which the differential of the function becomes equal to zero.

Differentiate the above expression.

f'(x)=8×13×x13-1+43×x43-1=83×x-23+43×x13

Equate the derivative of the function to zero.

83×x-23+43×x13=083×x-23=-43×x138×x-23=-4×x13-2=x13x-23x=-2 and x=0

Thus, the critical point of the function is at x=-2 and x=0.

Thus, the intervals of the functions are,

(-,2) and (0,)

The value of the derivative of the function is negative on the interval,(-2,), thus, the function is decreasing on the interval.

The derivative of the function is positive on the interval (2,)

Thus, the function increases on the interval (2,)

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