Determine the general/particular solution (whichever applies): y''+ 4y'+ 4y = (3+x)e-2x, when x = 0, y = 2, y'=5 O 3 * +(²+²+ + ²) + -2x y=2e -2x - xe y=2e-2x3xe -2x y = 2e + 9xe -2x - ² + ( x ³ + 3 x ³) = ² -2x y=2e²x + 4xe 2x + + -212x₁² xe - + x³ + x²) ²2 2x 4

Q: {3x+y=-3 2x+3y=5 (X,y) =

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Q: find x and y if (2x+1,y)=(5x+4, -7)

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Q: Find an explicit solution to the initial value problem: dy = dx y(x) = ex - 5y y(0) = 0

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Q: 4.у%3D (2х — х3)(2х + 1)

A: Follow the procedure given below.

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Q: Determine the solutions of: y^n  + 4y  = 0 y(-π) = y(π), y´(-π) = y´(π)

A:

Q: Given y=63x+1, find y". A 3x(3x+1)63x-1 B (9)63*+1 © 63x+1 D (3in6)263*+1

A: Given, y =63x+1 then y'' = ?

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A:

Q: 2. Use undetermined coefficients method to solve 1 yi = 4yı + 2 - 3e", y2 = 9y1 + 6y2 + 10e'.

A:

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A: The given equation is,

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Q: Verify that y = ODE y" + 3y' + 2y = 4x². -4e-x-2e-2x + 2x² - 6x +7 is a solution of the SHOW ALL…

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