Determine the formula of the hydrocarbon compound where m/z=134. The mass spectrum indicates an M+2 peak in a 3:1 ratio. The IR spectrum also indicates a strong peak at 1760 cm1
Analyzing Infrared Spectra
The electromagnetic radiation or frequency is classified into radio-waves, micro-waves, infrared, visible, ultraviolet, X-rays and gamma rays. The infrared spectra emission refers to the portion between the visible and the microwave areas of electromagnetic spectrum. This spectral area is usually divided into three parts, near infrared (14,290 – 4000 cm-1), mid infrared (4000 – 400 cm-1), and far infrared (700 – 200 cm-1), respectively. The number set is the number of the wave (cm-1).
IR Spectrum Of Cyclohexanone
It is the analysis of the structure of cyclohexaone using IR data interpretation.
IR Spectrum Of Anisole
Interpretation of anisole using IR spectrum obtained from IR analysis.
IR Spectroscopy
Infrared (IR) or vibrational spectroscopy is a method used for analyzing the particle's vibratory transformations. This is one of the very popular spectroscopic approaches employed by inorganic as well as organic laboratories because it is helpful in evaluating and distinguishing the frameworks of the molecules. The infra-red spectroscopy process or procedure is carried out using a tool called an infrared spectrometer to obtain an infrared spectral (or spectrophotometer).
![### Hydrocarbon Compound Analysis
**Problem Statement:**
Determine the formula of the hydrocarbon compound where m/z = 134. The mass spectrum indicates an M+2 peak in a 3:1 ratio. The IR spectrum also indicates a strong peak at 1760 cm⁻¹.
**Analysis:**
1. **Mass Spectrum Analysis:**
- The mass spectrum of the compound shows a molecular ion peak (M) at m/z = 134.
- The presence of an M+2 peak with a 3:1 ratio suggests the presence of chlorine (Cl) in the compound. Chlorine naturally occurs as two isotopes: ^35Cl and ^37Cl, with a relative abundance ratio of approximately 3:1.
2. **IR Spectrum Analysis:**
- The IR spectrum shows a strong absorption peak at 1760 cm⁻¹. This is indicative of a carbonyl group (C=O), typically found in ketones, aldehydes, or esters.
**Conclusion:**
To find the formula, considering the presence of chlorine and a carbonyl group, and the molecular ion peak:
- Assuming the simplest structure, a mono-halogenated compound (one chlorine atom) with a carbonyl group, and calculating the rest of the molecular mass:
The atomic mass of chlorine (^35Cl) is approximately 35.
The mass of the remaining part of the molecule (134 - 35 = 99) should be composed of carbon (C), hydrogen (H), and oxygen (O) atoms.
For precise formula determination, the exact structure needs more details, but one plausible candidate is a compound like trichloroacetone (C3H3Cl3O).
**Answer:**
(Note: Depending on the educational focus, further study or details might be required to confirm and elaborate on the exact structure and formula.)
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